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Sunny_sXe [5.5K]
3 years ago
12

Find the coordinate of the midpoint M given the two endpoints

Mathematics
1 answer:
Rasek [7]3 years ago
8 0

The midpoint would be (7, 5)

The midpoint of any two points is simply the average of the x points and the average of the y points. So we'll start by averaging the 2 x points together. To take an average, we add the two numbers together and divide by 2.

X VALUE

4 + 10 = 14

14/2 = 7

Now do the same for y

Y VALUE

22 + -12 = 10

10/2 = 5

Using those answers we can create the ordered pair (7, 5)

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29 = 5a + 4
25 = 5a
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3 years ago
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20 - 4 { 20÷ 7 ( 7 - 3 )}​
hodyreva [135]

20 -4 { 20÷ 7 ( 7 - 3 )}

20 -4 { 20 ÷ 7 * 4 }

20 - 4 { 2.85 * 4 }

16 * 11.42

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4 0
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Find the difference when the polynomial -5x^2+3x+8 is subtracted from the polynomial 2x^2+4x+1.
geniusboy [140]

The difference is 7x^{2}  + 1x-7.

Step-by-step explanation:

Step 1:

The polynomial -5x^{2}+3x+8 is subtracted from the polynomial 2x^{2} + 4x +1.

If we write this as an equation, we get

(2x^{2} + 4x +1) -(-5x^{2}+3x+8).

To subtract the polynomials, we group up the terms based on their variables.

In this subtraction, there are two variables i.e. x^{2} and x and there is one constant term.

Step 2:

The subtraction of the x^{2} variables; 2x^{2}  -(-5x^{2} )  = 2x^{2} +5x^{2} = 7x^{2}.

The subtraction of the x variables; 4x - (3x) = 1x.

The subtraction of the constants; 1-(8) = -7.

So (2x^{2} + 4x +1) -(-5x^{2}+3x+8) = 7x^{2}  + 1x-7.

4 0
2 years ago
93% of what number is 25?​
marta [7]

Answer: The answer is 327

Explanation: 93×100/25 = 327

6 0
3 years ago
2x² - 5x+1 has roots alpha and beta. Find alpha⁴+beta⁴ without solving the equation.
shepuryov [24]

Answer:

Step-by-step explanation:

\alpha+\beta=\dfrac{5}{2} \\\\\alpha*\beta=\dfrac{1}{2} \\\\\alpha^2+\beta^2=\dfrac{21}{4} \ (see\ previous\ post)\\\\(\alpha+\beta)^4=\dfrac{625}{16} \\\\=\alpha^4+\beta^4+4*\alpha^3*\beta+6*\alpha^2*\beta^2+4*\alpha*\beta^3\\\\=\alpha^4+\beta^4+4*(\alpha*\beta)(\alpha^2+\beta^2)+6*\alpha^2*\beta^2\\\\\alpha^4+\beta^4=(\alpha+\beta)^4-4*(\alpha*\beta)(\alpha^2+\beta^2)-6*\alpha^2*\beta^2\\\\= \dfrac{625}{16} -4*\dfrac{1}{2} *\dfrac{21}{4} -6*(\dfrac{1}{2})^2 \\\\

= \dfrac{625}{16}- \dfrac{168}{16}-\dfrac{24}{16}\\\\\\= \dfrac{433}{16}

7 0
2 years ago
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