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4 years ago

Give one number that makes the inequality x + 7 > 20 true

Mathematics

1 answer:

Zigmanuir [339]4 years ago

7 0

For example smallest x which makes inequelity is x =14
because 14 + 7 = 21 > 20

you can take any number >= 14

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Simply (tan^2 x - sec^2 x)(sin^2 x + cos^2 x)

kati45 [8]

we can use pythagorean identieis

remember that $sin^2(x)+cos^2(x)=1$

also remember that $tan(x)=\frac{sin(x)}{cos{x}}$ and $sec(x)=\frac{1}{cos(x)}$

so if we take $sin^2(x)+cos^2(x)=1$ and divide both sides by $cos^2(x)$ we get

$\frac{sin^2(x)}{cos^2(x)}+\frac{cos^2(x)}{cos^2(x)}=\frac{1}{cos^2(x)}$

$(\frac{sin(x)}{cos(x)})^2+1=(\frac{1}{cos(x)})^2$

$tan^2(x)+1=sec^2(x)$

subtracting $1+sec^2(x)$ from both sides

$tan^2(x)-sec^2(x)=-1$

now subsitute into original problem

$\frac{tan^2(x)-sec^2(x)}{sin^2(x)+cos^2(x)}=$

$\frac{-1}{1}=$

$-1$

the answer is -1

6 0

3 years ago

A plant in the manufacturing sector is concerned about its sulfur dioxide emissions. The weekly sulfur dioxide emissions follow

egoroff_w [7]

Answer:

The correct option is b) 1.70

Step-by-step explanation:

Consider the provided information.

The weekly sulfur dioxide emissions follow a normal distribution with a mean of 1000 ppm (parts per million) and a standard deviation of 25.

Thus, μ=1000 and σ = 25

The CEO wants to know if the mean level of emissions is different from 1000.

Therefore the null and alternative hypothesis is:

$H_0:\mu =1000$ and $H_a:\mu \neq1000$

The sample size is n = 50 and $\bar x=1006$ ppm.

Now calculate the test statistic by using the formula: $z=\frac{\bar x-\mu}{\frac{\sigma}{\sqrt{n}}}$

Substitute the respective values in the above formula.

$z=\frac{1006-1000}{\frac{25}{\sqrt{50}}}$

$z=\frac{6}{\frac{25}{\sqrt{50}}}=1.697\approx 1.70$

Hence, the correct option is b) 1.70

7 0

3 years ago

A stereo speaker in the shape of a triangular pyramid has a height of 8.25 inches. The area of the base of the speaker is 22 squ

alexandr1967 [171]

Answer:

A. 60.5 $in^{3}$

Step-by-step explanation:

A = 1/3(area of base)(h)

= 1/3(22)(8.25)

= 60.5 $in^{3}$

7 0

3 years ago

Read 2 more answers

Jared started a new job. On the first day he had orientation and worked for 2 hours. On the second day he trained for 4 hours. A

tresset_1 [31]

Answer:

Jared worked 11 days as full 8-hour days.

Step-by-step explanation:

We have:

First day = 2 h

Second day = 4 h

After that = 8 h each day

Since his paycheck shows 94 hours of work, we can find the number of days that he works 8-hour day:

$94 h = 2 h + 4 h + 8 h*x$

Where x is the number of days that he works 8-hours.

$8 h*x = 88 h$

$x = \frac{88 h}{8 h} = 11$

Therefore, Jared worked 11 days as full 8-hour days.

I hope it helps you!

5 0

3 years ago

Solve the inequality T> L+D

nirvana33 [79]

Answer:

solving for t= t>d+l

For l= l<t-d

Then for d=d<t-l

4 0

3 years ago