How many orders of fried chicken
2 answers:
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we are given
Here,
y is the number of gallons of water in the pool
x is the number of minutes the truck has been filing the pool
now, we will verify each options
option-A:
When x=1
then y=19.75
so, for 1 minute , number gallons =19.75
so, this is FALSE
option-B:
Since, we have
It is similar to equation of line
y=mx+b
But b=0
It means that it passes through origin
so, this is TRUE
option-C:
we can compare it with
y=mx
where m is the rate
so, we get
while we are given
the water in swimming pool increase about 100 gallons by every 5 minutes
so, we get rate as
gallons per minute
this is close to 19.75
so, they are approximately equal
so, this is TRUE
option-d:
x-value and y-value will show relationship
and ratio will always be constant or equivalent
because it has linear relationship
so, this is TRUE
option-e:
We need to check
(8,150) ..so, x=8 and y=150
we can plug this in our equation
and we get
Since, left side is not equal to right side
so, this can not be point
so, this is FALSE
Answer:
The conditions for use of the normal model to represent the distribution of sample proportion are not met. He should increase the sample size until the conditions are met.
If the test is done anyway, the null hypothesis failed to be rejected.
The conclusion is taht there is not enough evidence to support the claim that the percentage is lower in this district.
Step-by-step explanation:
The conditions for use of the normal model to represent the distribution of sample proportion are not met, as the affirmative responses are less than 10.
If the test of hypothesis is done as if the conditiones were met, we know that the claim is that the percentage is lower in this district.
Then, the null and alternative hypothesis are:
The significance level is 0.05.
The sample has a size n=80.
The sample proportion is p=0.1.
The standard error of the proportion is:
Then, we can calculate the z-statistic as:
This test is a left-tailed test, so the P-value for this test is calculated as:
As the P-value (0.057) is greater than the significance level (0.05), the effect is not significant.
The null hypothesis failed to be rejected.
There is not enough evidence to support the claim that the percentage is lower in this district.