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Rudik [331]
3 years ago
14

The access code for a​ car's security system consists of four digits. the first digit cannot be 6 and the last digit must be eve

n. how many different codes are​ available?
Mathematics
1 answer:
sertanlavr [38]3 years ago
5 0
There are 9 choices for the first digit: {0, 1, 2, 3, 4, 5, 7, 8, 9}
There are 10 choices for the second digit: {0, 1, 2, 3, 4, 5, 6, 7, 8, 9}
There are 10 choices for the third digit: {0, 1, 2, 3, 4, 5, 6, 7, 8, 9}
There are 5 choices for the fourth digit: {0, 2, 4, 6, 8}

Multiply the number of choices per digit to get: 9*10*10*5 = 90*50 = 4500

Answer: 4500
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Answer:

Step-by-step explanation:

Null hypothesis: National proportion P ≥ sample proportion

Alternative hypothesis: National proportion P < sample proportion

Collect the Data.

Sample size n = 348, population proportion P = 0.41,

a. What is the sample proportion? Use 4 decimal places.

Sample proportion p = 132/348 = 0.3793

b. What is the standard deviation for this problem?

The standard deviation can be calculated using this formula:

√[(p x (1-p)) / n] = √[(0.3793 x (1 - 0.3793) / 348

= √[(0.3793 x 0.6203) / 348]

 = √(0.2354 / 348)

= √0.0006765

SD = 0.026

c. The conditions are met:

The sampling method is simple random sampling: Yes

Each sample point can result in just two possible outcomes: a success; have engaged in binge drinking and a failure: have not engaged in binge drinking

The sample includes at least 216 failures and 132 successes

The population size is at least 20 times as big as the sample size: college students nationwide are even 20 times more than 348.

d) What is the test statistic?

z = (p - P) / σ

z = (0.3793 - 0.41) / 0.026

z = (-0.0307 / 0.026)

z = -1.18

At a 5% level of significance, where α= 0.05, p value for -1.18 for a one tailed test using the p value calculator is  0.119, the result is not significant at p < .05 thus, concluding that we fail to reject the null as there is not enough evidence to conclude students enrolled at this college that binge drink is lower than the national proportion of students that binge drink

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