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2 years ago

Evaluate the function as indicated determine its domain and range.

1 answer:

7 0

<span>-1<0 so use 2x+1 2(-1)+1=-2+1=-1 -
</span><span>F(-1) means "Evaluate F(x) when x=-1" Since -1 is less than 0, this means that F(x) = 2x+1. This is because F(x) = 2x+1 when x < 0</span>

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if the ratio of home fans to visiting fans is 5:2 and all 42000 seats in a stadium are filled, how many visiting fans are in att

jeka94

Answer:

12000

Step-by-step explanation:

Sum the parts of the ratio, 5 + 2 = 7

Divide the total seats by 7 to find the value of one part of the ratio

42000 ÷ 7 = 6000 ← value of 1 part of the ratio

visiting fans = 2 × 6000 = 12000

8 0

2 years ago

I have this question that i dont get plz help-2|2.2x-3.3|=-6.6

maria [59]

Step-by-step explanation:

Absolute value of a number gives the positive quantity of the number.

For instance,

$|3|=3, |-3|=3$

From this example, therefore we know that

$\text{If }|x|=a,\text{ then }x=a\text{ or } -a.$

--------------------------------------------

In this question,

$-2|2.2x-3.3|=-6.6$

$|2.2x-3.3|=3.3$

$2.2x-3.3=3.3\text{ or } -3.3$

$2.2x=3.3+3.3 \text{ or }-3.3+3.3$

$2.2x=6.6\text{ or } 0$

$x=3\text{ or } 0$

8 0

2 years ago

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PLEASE HELP!!!!! I BEG OF EVERYONE. FIRST CORRECT WILL GET BRALIEST!!!!!!! How far have I travelled if I biked at 10mph for hhrs

prohojiy [21]

Answer:

32 miles/4 hours.

Step-by-step explanation:

7 0

2 years ago

Read 2 more answers

<img src="https://tex.z-dn.net/?f=%28x%5E%7B2%7D%20%2Bx-3%29%3A%20%28x%5E%7B2%7D%20-4%29%5Cgeq%201" id="TexFormula1" title="(x^{

Jlenok [28]

Answer:

$x>2$

Step-by-step explanation:

When given the following inequality;

$(x^2+x-3):(x^2-4)\geq1$

Rewrite in a fractional form so that it is easier to work with. Remember, a ratio is another way of expressing a fraction where the first term is the numerator (value over the fraction) and the second is the denominator(value under the fraction);

$\frac{x^2+x-3}{x^2-4}\geq1$

Now bring all of the terms to one side so that the other side is just a zero, use the idea of inverse operations to achieve this:

$\frac{x^2+x-3}{x^2-4}-1\geq0$

Convert the (1) to have the like denominator as the other term on the left side. Keep in mind, any term over itself is equal to (1);

$\frac{x^2+x-3}{x^2-4}-\frac{x^2-4}{x^2-4}\geq0$

Perform the operation on the other side distribute the negative sign and combine like terms;

$\frac{(x^2+x-3)-(x^2-4)}{x^2-4}\geq0\\\\\frac{x^2+x-3-x^2+4}{x^2-4}\geq0\\\\\frac{x+1}{x^2-4}\geq0$

Factor the equation so that one can find the intervales where the inequality is true;

$\frac{x+1}{(x-2)(x+2)}\geq0$

Solve to find the intervales when the equation is true. These intervales are the spaces between the zeros. The zeros of the inequality can be found using the zero product property (which states that any number times zero equals zero), these zeros are as follows;

$-1, 2, -2$

Therefore the intervales are the following, remember, the denominator cannot be zero, therefore some zeros are not included in the domain

$x\leq-2\\-2$

Substitute a value in these intervales to find out if the inequality is positive or negative, if it is positive then the interval is a solution, if it is negative then it is not a solution. This is because the inequality is greater than or equal to zero;

$x\leq-2$ -> negative