There are no real numbers that can do that job.
There's a pair of complex numbers that can do it.
They are
4.5 + i23.23
and
4.5 - i23.23 .
' i ' = the imaginary unit = √(-1)
DrH = DrT + 0.019
DrE = DrH - 0.020
DrH is the most and DrE is the least
If 3 inch....................................20 ft
?inc...........................................57 feet
(57*3)/20=171/20=8.55 inch
Answer:
x is equal to -9 thus it becomes -18 in the whole setup
Answer:
The amount of Polonium-210 left in his body after 72 days is 6.937 μg.
Step-by-step explanation:
The decay rate of Polonium-210 is the following:
(1)
Where:
N(t) is the quantity of Po-210 at time t =?
N₀ is the initial quantity of Po-210 = 10 μg
λ is the decay constant
t is the time = 72 d
The decay rate is 0.502%, hence the quantity that still remains in Alexander is 99.498%.
First, we need to find the decay constant:
(2)
Where t(1/2) is the half-life of Po-210 = 138.376 days
By entering equation (2) into (1) we have:
Therefore, the amount of Polonium-210 left in his body after 72 days is 6.937 μg.
I hope it helps you!