The volume of the frustum is volume of the whole cone(A) minus the smaller cone(B) which is would give the volume of frustum(C) = 256cm³
<h3>Calculation of a frustum</h3>
The volume of cone A V=πr²h/3
Where radius = 20cm
The volume of cone B = V=πr²h/3
Where radius = 12cm
Therefore volume of frustum =
V=π * 20² * h/3 - π * 12² *h/3
The variables will cancel out each other
V = 20² - 12²
V = 400- 144
V = 256cm³
Therefore, the volume of the frustum(C) = 256cm³
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The only thing you could factor out is X so it would be
X(4x-5)
Answer:
The answer is -13.
Step-by-step explanation:
=4×(-2)-5
=-8-5
=-13
The value of (-2) is -13.
Answer:
The answer is c
Step-by-step explanation:
My original answer got deleted i dont know the reason.
Step-by-step explanation:
9x - 2 = 4x + 8 → (9-4)x = 8 + 2 → 5x = 10 → x = 10/2 = 5
C. multiplication
Multiplication not used
