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vaieri [72.5K]
3 years ago
12

Use multiplication in the distributive property to find the quotient 252 divided by 9

Mathematics
1 answer:
ira [324]3 years ago
8 0

252 divided by 9 is 28

Firstly, I muplity 20 and 9.

I have 180.

Then I also muplity 8 and 9.

I got 72.

Then I add 72 and 180 which got me 252.

(I hope this helped!)

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Helga [31]

Answer:

Math-way helps with algebra, hope you find the answer!

Step-by-step explanation:

7 0
3 years ago
HW 7.4/7.5 help mhhhh
Hatshy [7]

Answer:

1. LI=18

2. x=10

3. Yes (Y)

4. Yes (Y)

5. x=15

6. x=18

7. x=8

8. x=6

   y=6.5

Step-by-step explanation:

1. LI/JL=KH/JK

Replacing the given values:

LI/6=21/7

Dividing on the right side of the equation:

LI/6=3

Solving for LI: Multiplying both sides of the equation by 6:

6(LI/6)=6(3)

LI=18


2.TV/VS=RU/US

Replacing the given values:

x/17.5=8/14

Simplifying the fraction on the right side of the equation: Dividing numerator and denominator by 2:

x/17.5=(8/2) / (14/2)

x/17.5=4/7

Solving for x: Multiplying both sides of the equation by 17.5:

17.5(x/17.5)=17.5(4/7)=(17.5/1)(4/7)

Multiplying:

x=(17.5 x 4) / (1 x 7)

x=70/7

Dividing:

x=10


3. BC is parallel to DE if AD/DB is equal to AE/EC:

AD/DB=15/12=(15/3) / (12/3)→AD/DB=5/4

AE/EC=10/8=(10/2) / (8/2)→AE/EC=5/4

Like AD/DB=5/4=AE/EC → BC is parallel to DE


4. BC is parallel to DE if AD/DB is equal to AE/EC:

AD/DB= 2DB / DB→AD/DB=2

AE/EC=30 / (AC-AE)=30 / (45-30)=30/15→AE/EC=2

Like AD/DB=2=AE/EC → BC is parallel to DE


5. If JH is a midsegment of triangle KLM:

x=(1/2)(30)

x=15


6. If JH is a midsegment of triangle KLM:

x=2(9)

x=18


7. If JH is a midsegment of triangle KLM: x=8


8. 2x+1=x+7

Solving for x. Grouping the x's on the left side of the equation: Subtracting x both sides of the equation:

2x+1-x=x+7-x

Subtracting:

x+1=7

Subtracting 1 both sides of the equation:

x+1-1=7-1

Subtracting:

x=6

2x+1=2(6)+1=12+1→2x+1=13

x+7=6+7→x+7=13


(3y-8)/(y+5)=(2x+1)/(x+7)

(3y-8)/(y+5)=13/13

(3y-8)/(y+5)=1

3y-8=y+5

Solving for y. Grouping the y's on the left side of the equation: Subtracting y both sides of the equation:

3y-8-y=y+5-y

Subtracting:

2y-8=5

Adding 8 both sides of the equation:

2y-8+8=5+8

Subtracting:

2y=13

Dividing both sides of the equation by 2:

2y/2=13/2

Dividing:

y=6.5



3 0
3 years ago
What is the interquartile range (IQR) of the following data set?
OleMash [197]

Answer:

9

Step-by-step explanation:

Arrange data set

19, 4, 17, 3, 6, 5,5, 3, 11, 12, 3, 7, 15, 8, 8, 10,5, 3, 12, 41, 36

in ascending order

3, 3, 3, 3, <u>4, 5,</u> 5, 5, 6, 7, 8, 8, 10, 11, 12, <u>12, 15,</u> 17, 19, 36, 41

The median is Q_2=8

Q_1=\dfrac{4+5}{2}=4.5  

Q_3=\dfrac{12+15}{2}=13.5

Thus, the interquartile range is

Q_3-Q_1=13.5-4.5=9

4 0
3 years ago
Can someone please help me
Salsk061 [2.6K]

Answer:

B

Step-by-step explanation:

Area of pool = l × b

l = 6x and b = 3x - 5

Area = 6x(3x - 5)

Area = 18x² - 30x

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3 years ago
At breakfast, restaurant charges $2 for the first cup of orange juice and then $1 for each refill which graph represents this si
liq [111]

Answer:

line

Step-by-step explanation:

y= 2+(x-1)*1= x+1

y=x+1

linear function, the graph is going to be a line

6 0
3 years ago
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