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Alexus [3.1K]
3 years ago
7

Find the third angle of a right triangle if one of the angles measures 24.

Mathematics
1 answer:
allochka39001 [22]3 years ago
5 0
In a right triangle, one angle should be a right angle, which means that angle should be 90°. Right angles are always 90°.

And in any triangle, the sum of the 3 interior angles should add up to 180°, this rule is always the same. Therefore, to find the third angle, we should simply subtract the angles we already know from the angle sum of triangle.

We can therefore list this equation:
Third angle = 180° - 24° - 90°
Third angle = 66°

Your answer should be 66°
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What is to compatible 287-162
WARRIOR [948]
Well 287-162=125 so, what numbers also equal the same?
well, lets say you had 469 cookies and only 344 were eaten. how many are left? 125 
So 469-344 is = to 287-162
6 0
3 years ago
(very urgent) will gave 20 pts
kakasveta [241]

Answer:

a. 45/1024

b. 1/4

c. 15/128

d. 193/512

e. 9/256

Step-by-step explanation:

Here, each position can be either a 0 or a 1.

So, total number of strings possible = 2^10 = 1024

a) For strings that have exactly two 1's,

it means there must also be exactly eight 0's.

Thus, total number of such strings possible

10!/2!8!=45

Thus, probability is

45/1024

b) Here, we have fixed the 1st and the last positions, and eight positions are available.

Each of these 8 positions can take either a 0 or a 1.

Thus, total number of such strings possible

=2^8=256

Thus, probability is

256/1024 = 1/4

c) For sum of bits to be equal to seven, we must have exactly seven 1's in the string.

Also, it means there must also be exactly three 0's

Thus, total number of such strings possible

10!/7!3!=120

Thus, probability

120/1024 = 15/128

d) Following are the possibilities :

There are six 0's, four 1's :

So, number of strings

10!/6!4!=210

There are seven 0's, three 1's :

So, number of strings

10!/7!3!=120

There are eight 0's, two 1's :

So, number of strings

10!/8!2!=45

There are nine 0's, one 1's :

So, number of strings

10!/9!1!=10

There are ten 0's, zero 1's :

So, number of strings

10!/10!0!=1

Thus, total number of string possible

= 210 + 120 + 45 + 10 + 1

= 386

Thus, probability is

386/1024 = 193/512

e) Here, we have fixed the starting position, so 9 positions remain.

In these 9 positions, there must be exactly two 1's, which means there must also be exactly seven 0's.

Thus, total number of such strings possible

9!/2!7!=36

Thus, probability is

36/1024 = 9/256

5 0
3 years ago
Find the surface area of the cube (above) using its net (below).
lana66690 [7]

\mathsf \green{ {96 \: units}^{2} }

8 0
2 years ago
A) Change 9 out of 50 to a percentage.​
Artist 52 [7]

Hey there! Your question’s answer would be 18%..

Ok so 9/50 would be 9% out of 50% which is also 100%. If you want to find 50% turn to 100%, multiply 50 with 2 to get 100.

So you do the same thing to 9%. 9 times 2 would be 18%.

Final Result: 9% out of 100% (whole)

6 0
2 years ago
A rectangular prism has a base area of 400 square inches. The volume of the prism is 2,400 cubic inches. What is the height of t
katrin [286]

Answer:

6

Step-by-step explanation:

2,400 divided by 400 = 6

7 0
3 years ago
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