GCF of 24 and 40 •Response• 》》》》》》》》》》》

A car starts a journey with a full tank of gas. The equation y=16 - 0.05x relates the number of gallons of gas, y, left in the t

GenaCL600 [577]

We are given that a car starts a journey with a full tank of gas. The equation $y=16-0.05x$ relates the number of gallons of gas (y) left in the tank to the number of miles the car has traveled(x).

A. We will find y intercept by substituting x=0 in our equation,

$y=16-0.05*0$

$y=16$

Now let us find our x-intercept by substituting y=0 in our equation,

$0=16-0.05x$

$0.05x=16$

$x=\frac{16}{0.05}=320$

Therefore, x-intercept is 320 and y-intercept is 16.

B. Our x-intercept represents that after travelling 320 miles there were 0 or none gallons of gas left in tank.

C. Our y-intercept represents that there were 16 gallons of gas in car tank when car started the journey.

6 0

3 years ago

Nar

malfutka [58]

Answer:27 divided by 3 to get 9 or add 3 repetitively to get 27 or 3x=27

Step-by-step explanation:

7 0

3 years ago

PLEASE HELP ON THESE 2

marishachu [46]

The answers to these problems are 1.B and 2.C

3 0

4 years ago

Is the graph a function or not? Why or why not?

yarga [219]

Answer:

No, it is not a function

Step-by-step explanation:

Using the vertical line test, you would find that it would hit two points, making it not a funtion.

7 0

3 years ago

Read 2 more answers

A ball is thrown vertically upwards from the ground. It rises to a height of 10m and then falls and bounces. After each bounce,

Citrus2011 [14]

${\huge{\fcolorbox{yellow}{red}{\orange{\boxed{\boxed{\boxed{\boxed{\underbrace{\overbrace{\mathfrak{\pink{\fcolorbox{green}{blue}{Answer}}}}}}}}}}}}}$

(i)

$\sf{a_n = 20 \times {( \frac{2}{3} )}^{n - 1} }$

(ii)

$\sf S_n = 60 \{1 - { \frac{2}{3}}^{n} \}$

Step-by-step explanation:

$\underline\red{\textsf{Given :-}}$

height of ball (a) = 10m

fraction of height decreases by each bounce (r) = 2/3

$\underline\pink{\textsf{Solution :-}}$

(i) We will use here geometric progression formula to find height an times

${\blue{\sf{a_n = a {r}^{n - 1} }}} \\ \sf{a_n = 20 \times { \frac{2}{3} }^{n - 1} }$

(ii) here we will use the sum formula of geometric progression for finding the total nth impact

$\orange {\sf{S_n = a \times \frac{(1 - {r}^{n} )}{1 - r} }} \\ \sf S_n = 20 \times \frac{1 - ( { \frac{2}{3} })^{n} }{1 - \frac{2}{3} } \\ \sf S_n = 20 \times \frac{1 - {( \frac{2}{3}) }^{n} }{ \frac{1}{3} } \\ \sf S_n = 3 \times 20 \times \{1 - ( { \frac{2}{3}) }^{n} \} \\ \purple{\sf S_n = 60 \{1 - { \frac{2}{3} }^{n} \}}$

4 0

2 years ago

GCF of 24 and 40•Response•》》》》》》》》》》》​

GCF of 24 and 40•Response•》》》》》》》》》》》