Answer:
year 7
Step-by-step explanation:
If we assume that investment A earns interest compounded annually, its value can be modeled by the equation ...
A = 50·(1+0.08)^(t-1) . . . . . where t is the year number
The second investment earns $3 per year, so its value can be modeled by the equation ...
B = 60 + 3(t -1) . . . . . . . . . where t is the year number
We are interested in finding the minimum value of t such that ...
A > B
50·1.08^(t-1) > 60 +3(t-1)
This is a mix of exponential and polynomial terms for which no solution method is available using the tools of Algebra. A graphing calculator shows the solution to be ...
t > 6.552
The value at the end of year 1 is found for t=1, so the values of interest are seen after 6.55 years, in year 7.
Answer:
x=17, y=12
Step-by-step explanation:
From the figure we know that,
Angle CDB = 4x-5
Angle BDE = 10y-3
Angle DEA= 97-2x
Though we are NOT given that line segments BD and AE are parallel, we may assume so by the construction of the triangle.
Hence, BD II AE and are cut by the transversal CE,
Hence,
Angle CDB = Angle CEA {Corresponding angles are equal}
As we observe that,
Angle CDB and Angle BDE form a linear pair, they are supplementary.
Hence,
Angle CDB + Angle BDE = 180
3.1,2,2/3,0.55,0, -7/8,-4