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Marianna [84]
3 years ago
6

painter A charges $376 plus $12 per and painter B charges $280 plus $15 per hour. in how many hours will they cost the same

Mathematics
2 answers:
sladkih [1.3K]3 years ago
7 0
In 32 hours they will cost the same
ohaa [14]3 years ago
4 0

Answer:

32 hours

Step-by-step explanation:

Let after x hours the charges of A and B are same,

Given,

For painter A,

Fixed charges = $ 376,

Additional charges per hour = $ 12,

So, the total charges for x hours = ( 376 + 12x ) dollars

For painter B,

Fixed charges = $ 280,

Additional charges pet hour = $ 15,

So, the total charges for x hours = ( 280 + 15x ) dollars

Thus,

376 + 12x = 280 + 15x

12x - 15x = 280 - 376

-3x = -96

x = 32

Hence, for 32 hours their cost will be same.

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4 years ago
What algebraic expression represents GK?
dsp73

Answer:

Part a) GK=(7x+1)

Part b) GH=5 units and JK=8 units

Step-by-step explanation:

Part a) what algebraic expression represents GK?

we know that

GK=GH+HJ+JK

step 1

Find GH

we have

GH=GJ-HJ

substitute the given values

GH=(2x+3)-x=x+3

step 2

Find JK

JK=HK-HJ

substitute the given values

JK=(6x-2)-x=5x-2

step 3

Find GK

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GH=x+3

HJ=x

JK=5x-2

substitute

GK=(x+3)+x+(5x-2)

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Part b) If GK=15, what are GH and JK?

we know that

GK=(7x+1)

For GK=15

substitute the value of GK and solve for x

15=(7x+1)

7x=15-1

7x=14

x=2

<u><em>Find the value of GH</em></u>

GH=x+3

substitute the value of x

GH=2+3=5 units

<u><em>Find the value of JK</em></u>

JK=5x-2

substitute the value of x

JK=5(2)-2=8 units

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