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4 years ago

Sarah has some chocolates.

Mathematics

1 answer:

kakasveta [241]4 years ago

8 0

Answer:

24:8 which is also just 6:2 or 3:1

Step-by-step explanation:

There are many ways you can write this, and this is what I think hope this helps

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The equation x²– 8x – 5 = 0 can be transformed into the equation (x - p)² = q, where p and q are real numbers. What are the valu

Juliette [100K]

The form (x - p)^2 = q is the form that completing the square will leave us with.

---Add 5 to both sides

x^2 - 8x = 5

---Divide the b term by 2, and square it. Then, add that number to both sides.

-8/2 = -4

(-4)^2 = 16

x^2 - 8x + 16 = 5 + 16

x^2 - 8x + 16 = 21

---Factor!

(x - 4)^2 = 21

p = 4

q = 21

Hope this helps!! :)

5 0

3 years ago

A small toy car costs $3.A large toy car costs 5 times as much as the small one.Aaron wants to buy one of each.Which equation ca

adell [148]

Answer:$18.00

Step-by-step explanation:5×3=15

$3+$15=$18

6 0

3 years ago

Read 2 more answers

Karen wants to join Buff Gym. There is a $100 initiation fee, and then a $40 monthly fee. A) Determine the equation that express

REY [17]

Sorry for the bad handwriting.

5 0

3 years ago

5. What is an equation for the line with slope and y-intercept 9? (1 point)

Semenov [28]

6.) y - (-3) = (1 - (-3))/(3 - 1) (x - 1)
y + 3 = (1 + 3)/2 (x - 1)
y + 3 = 4/2 (x - 1)
y + 3 = 2(x - 1) = 2x - 2
y = 2x - 2 - 3 = 2x - 5
y = 2x - 5

4 0

3 years ago

Is square root 1 minus sine squared theta = cos Θ true? If so, in which quadrants does angle Θ terminate?

Cloud [144]

Answer:

True; quadrants I & IV

Step-by-step explanation:

We know the relation between sine and cosine function which is given by

$\sin^2 \theta +\cos^2 \theta = 1$

Let us solve this equation for cosine function.

$\cos^2 \theta = 1-\sin^2 \theta$

Take square root both sides. When ever we take square root we need to write the solution in plus minus form

$\sqrt{\cos^2 \theta}=\pm\sqrt{1-\sin^2 \theta}$

$\cos \theta=\pm\sqrt{1-\sin^2 \theta}$

$\cos \theta=-\sqrt{1-\sin^2 \theta}, \sqrt{1-\sin^2 \theta}$

If Θ is in quadrants I and IV then the value will be positive and if Θ is in II and III quadrant then the value is negative.

Hence, if Θ is in quadrants I & IV, then we have

$\cos \theta=\sqrt{1-\sin^2 \theta}$

Thus, the correct option is: True; quadrants I & IV

6 0

4 years ago

Read 2 more answers