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gavmur [86]
3 years ago
11

Sarah has some chocolates.

Mathematics
1 answer:
kakasveta [241]3 years ago
8 0

Answer:

24:8 which is also just 6:2 or 3:1

Step-by-step explanation:

There are many ways you can write this, and this is what I think hope this helps

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Differentiate. The answer is supposed to be -3/ sqrt 4-x^2
Margarita [4]

Answer:

Step-by-step explanation:

g(x)=\cos^{-1} (\frac{x}{2})\\g'(x)= \frac{- 1}{\sqrt{1-(\frac{x}{2})^2}}*\frac{1}{2} \\=\frac{-1}{\sqrt{4-x^2} }

6 0
3 years ago
Jordan went to the store to buy a bicycle that was advertised for $50. When he arrived, he learned that the model he wanted was
Alika [10]
50 + 0.15(50) = 50 + 7.50 = 57.50 <==
3 0
3 years ago
Read 2 more answers
2. You are trying to determine which box of Honey Nut Cheerios to buy. The Family Size box weighs
mihalych1998 [28]

Answer:

Step-by-step explanation:

Of course it is MEGA, it is a common sense for everyone to know that buying bigger bulk results in cheaper price. But I will do the math for you:

MEGA size: 5 / 29.4 = 0.17 dollars per pound

Family size: 3.64 / 19.5 = 0.19 dollars per pound

so it is MEGA

5 0
3 years ago
Does anyone know the answer to this?
Alex

Answer:

10.5.

Step-by-step explanation:

By similar  triangles:

IJ / 21 = 8 /(8+8) = 1/2

IJ / 21 = 1/2

IJ = 1/2 * 21

= 10.5.

6 0
2 years ago
Integral of 17/(x^3-125)
daser333 [38]

Answer:

17/75 ln│x − 5│− 17/150 ln(x² + 5x + 25) − 17/(5√75) tan⁻¹((2x + 5) / √75) + C

Step-by-step explanation:

∫ 17 / (x³ − 125) dx

= 17 ∫ 1 / (x³ − 125) dx

= 17 ∫ 1 / ((x − 5) (x² + 5x + 25)) dx

Use partial fraction decomposition:

= 17 ∫ [ A / (x − 5) + (Bx + C) / (x² + 5x + 25) ] dx

Use common denominator to find the missing coefficients.

A (x² + 5x + 25) + (Bx + C) (x − 5) = 1

Ax² + 5Ax + 25A + Bx² − 5Bx + Cx − 5C = 1

(A + B) x² + (5A − 5B + C) x + 25A − 5C = 1

Match the coefficients and solve the system of equations.

A + B = 0

5A − 5B + C = 0

25A − 5C = 1

A = 1/75

B = -1/75

C = -2/15

So the integral is:

= 17 ∫ [ 1/75 / (x − 5) + (-1/75 x − 2/15) / (x² + 5x + 25) ] dx

Simplify:

= 17/75 ∫ [ 1 / (x − 5) − (x + 10) / (x² + 5x + 25) ] dx

Factor ½ from the numerator of the second fraction:

= 17/75 ∫ [ 1 / (x − 5) − ½ (2x + 20) / (x² + 5x + 25) ] dx

Split the fraction:

= 17/75 ∫ [ 1 / (x − 5) − ½ (2x + 5) / (x² + 5x + 25) − ½ (15) / (x² + 5x + 25) ] dx

Multiply the last fraction by 4/4:

= 17/75 ∫ [ 1 / (x − 5) − ½ (2x + 5) / (x² + 5x + 25) − 30 / (4x² + 20x + 100) ] dx

Complete the square:

= 17/75 ∫ [ 1 / (x − 5) − ½ (2x + 5) / (x² + 5x + 25) − 15 / ((2x + 5)² + 75) ] dx

Split the integral:

= 17/75 ∫ 1 / (x − 5) dx − 17/150 ∫ (2x + 5) / (x² + 5x + 25) dx − 17/5 ∫ 1 / ((2x + 5)² + 75) dx

The first integral is:

∫ 1 / (x − 5) dx = ln│x − 5│

The second integral is:

∫ (2x + 5) / (x² + 5x + 25) dx = ln(x² + 5x + 25)

The third integral is:

∫ 1 / ((2x + 5)² + 75) dx = 1/√75 tan⁻¹((2x + 5) / √75)

Plug in:

= 17/75 ln│x − 5│− 17/150 ln(x² + 5x + 25) − 17/(5√75) tan⁻¹((2x + 5) / √75) + C

4 0
3 years ago
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