Ok so
t=number of text messsages
p=number of picture messages
total number is 33
t+p=33
if text is 0.18 per pic and picture is 0.45 per text
total cost is 8.3
0.18t+0.45p=8.3
times 100 both sides for ease
18t+45p=830
we now have 2 equations
t+p=33
18t+45p=830
multiply first equation by -18 and add to second equation
18t+45p=830
<span>-18t-18p=-594 +</span>
0t+27p=236
27p=236
divide both sides by 27
p=8.740740740740744
this is impossible becasue you can't send 0.740740740740744 of a message so you did a mistype somewhere
I believe x is 30 degrees.
The equilateral triangle has each angle equal to 60 degrees. So the small arc near x is also 60. The angle x is half the arc so would be 30.
This also makes sense because the triangle it forms with angle x and the center has center angle of 60 and angle formed by tangent and radius of 90. So it is a 30-60-90 triangle, making angle x 30.
A Rhombus has four equal straight sides. We can assume that the rhombus in this problem is square-shaped with 90° angles.
m1 = 18x ; 90 = 18x ; 90/18 = x ; 5 = x
m2 = x + y ; 90 = 5 + y ; 90 - 5 = y ; 85 = y
m3 = 30z ; 90 = 30z ; 90/30 = z ; 3 = z
x = 5 ; y = 85 ; z = 3
x + y + z ⇒ 5 + 85 + 3 = 93
