I reallyyy need help on these two questions please help ❤

n Juanita's Art History class Quizzes are worth 15% of the final grade, Exams are worth 55%, Projects are worth 25%, and Attenda

kvv77 [185]

Answer:

90.75%

Step-by-step explanation:

Given;

Of the total final score;

Quizzes = 15%

Exam = 55%

Project = 25%

Attendance = 5%

Resolving the values of each section of the total score;

she had perfect attendance to class. 100% attendance;

Attendance = 5% of total score

She got extra credit on her project with a score of 26 out of 25 possible points.

Project = 26/25 × 25% = 26%

80, 85, and 96 on the first three exams,each worth 100 points;

Total exam score = 80+85+96 = 261 out of 300

Of the total score;

Exam = 261/300 × 55% = 47.85%

At mid-semester Juanita scored 119 out of 150 points on quizzes.

Quizzes = 119/150 × 15% = 11.9%

Total exam score is;

= Quizzes+exam +project+attendance

= 11.9% + 47.85% + 26% + 5%

= 90.75%

3 0

2 years ago

Do circumstance of a circle with 17ft

olchik [2.2K]

Answer:

The circumference and area of a circle with a 17 ft diameter are:

C = 53.4 ft

A = 227 ft2

5 0

3 years ago

Nationwide, it is estimated that 40% of service stations have gas tanks that leak to some extent. A new program in California is

fredd [130]

Answer:

Since the calculated value of z= -1.496 does not fall in the critical region z < -1.645 we conclude that the new program is effective. We fail to reject the null hypothesis .

Step-by-step explanation:

The sample proportion is p2= 7/27= 0.259

and q2= 0.74

The sample size = n= 27

The population proportion = p1= 0.4

q1= 0.6

We formulate the null and alternate hypotheses that the new program is effective

H0: p2> p1 vs Ha: p2 ≤ p1

The test statistic is

z= p2- p1/√ p1q1/n

z= 0.259-0.4/ √0.4*0.6/27

z= -0.141/0.09428

z= -1.496

The significance level ∝ is 0.05

The critical region for one tailed test is z ≤ ± 1.645

Since the calculated value of z= -1.496 does not fall in the critical region z < -1.645 we conclude that the new program is effective. We fail to reject the null hypothesis .

8 0

3 years ago

Marina is paid $ 28 per hour and works 7 days per hour. She recives one paid day off foe each days that shd works what is her tr

Jobisdone [24]

I believe her hourly wage is $14/h because since she works an unpaid day for every day she does work. Therefore the 50% of her daily wage goes to the next day...

3 0

3 years ago

Suppose you'd like to save enough money to pay cash for your next car. The goal is to save an extra $28,000 over the next 6 year

Anna35 [415]

Given:

• Amount to save, A = $28,000

,

• Time, t = 6 years

,

• Interest rate, r = 5.3% ==> 0.053

,

• Number of times compounded = quarterly = 4 times

Let's find the amount that must be deposited into the account quarterly.

Apply the formula:

$FV=P(\frac{(1+\frac{r}{n})^{nt}-1}{\frac{r}{n}})$

Where:

FV is the future value = $28,000

r = 0.053

n = 4

t = 6 years

Thus, we have:

$28000=P(\frac{(1+\frac{0.053}{4})^{4\times6}-1)}{\frac{0.053}{4}}$

Let's solve for P.

We have:

$\begin{gathered} 28000=P(\frac{(1+0.01325)^{24}-1}{0.01325}) \\ \\ 28000=P(\frac{(1.01325)^{24}-1)^{}}{0.01325}) \\ \\ 28000=P(\frac{1.371509114-1}{0.01325}) \\ \\ 28000=P(\frac{0.371509114}{0.01325}) \end{gathered}$

Solving further:

$28000=P(28.0384237)$

Divide both sides by 28.0384237:

$\begin{gathered} \frac{28000}{28.0384237}=\frac{P(28.0384237)}{28.0384237} \\ \\ 998.6=P \\ \\ P=998.6 \end{gathered}$

Therefore, the amount that must be deposited quarterly into the account is $998.60

ANSWER:

$998.60

8 0

1 year ago