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maks197457 [2]
3 years ago
13

What is the length of AA' ?

Mathematics
2 answers:
hram777 [196]3 years ago
5 0
I hope this helps you

Lesechka [4]3 years ago
3 0
<span>Use the distance formula to solve this:
What is the length of AA' ?
</span>√(5-0)² + (2-0)²
<span>= 5.38
What is the length of BB' ?
</span>√(5-0)² + (4-2)²
= 5.38<span>
Since the translation is just moving the figure, the length of </span><span>CC'  and DD' is also 5.38</span>
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What is the value of 3/5+2/7
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0.8 is your answer

Step-by-step explanation:

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How many zeros does the function f(x) = 3x12 − 17x8 + 11x4 − 6x + 23 have?
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How many zeros does the function f(x) = 3x12 − 17x8 + 11x4 − 6x + 23 have? 

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3 years ago
Consider the probability that greater than 94 out of 153 people will not get the flu this winter. Assume the probability that a
Hatshy [7]

Answer:

0.8212 = 82.12% probability that greater than 94 out of 153 people will not get the flu this winter.

Step-by-step explanation:

Binomial probability distribution

Probability of exactly x sucesses on n repeated trials, with p probability.

Can be approximated to a normal distribution, using the expected value and the standard deviation.

The expected value of the binomial distribution is:

E(X) = np

The standard deviation of the binomial distribution is:

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Normal probability distribution

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

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When we are approximating a binomial distribution to a normal one, we have that \mu = E(X), \sigma = \sqrt{V(X)}.

In this problem, we have that:

p = 0.65, n = 153. So

\mu = E(X) = 153*0.65 = 99.45

\sigma = \sqrt{V(X)} = \sqrt{np(1-p)} = \sqrt{153*0.65*0.35} = 5.9

Consider the probability that greater than 94 out of 153 people will not get the flu this winter

This probability is 1 subtracted by the pvalue of Z when X = 94. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{94 - 99.45}{5.9}

Z = -0.92

Z = -0.92 has a pvalue of 0.1788

1 - 0.1788 = 0.8212

0.8212 = 82.12% probability that greater than 94 out of 153 people will not get the flu this winter.

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