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3 years ago

Find the period of the function. y=-3 cos 1/4x a. pi/4 b.-3 c.3pi/4 d.8pi

Mathematics

1 answer:

timofeeve [1]3 years ago

5 0

The answer is 1/4 = 2pi * 1/T, so T = 4*2pi = 8pi
so it is d.8pi

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Due to random variations in the operation of an automatic coffee machine, not every cup is filled with the same amount of coffe

DaniilM [7]

Answer:

465

because it is the wright answer

5 0

3 years ago

A rectangular magazine cover is photocopied by using a scale factor of One-third. The length of the photocopy of the magazine co

seraphim [82]

Answer: "reduced by a factor of One-third."

Step-by-step explanation:

Suppose that the original magazine has a length L and a width W.

If it is photocopied using a scale factor of K, then the measures of the photocopy will be:

length = K*L

Width = K*W

In this case, the scale factor is K = 1/3, then the measures of the photocopy will be:

length = (1/3)*L = L/3

Width = (1/3)*W = W/3

For usual notation:

When k > 1, we have an enlargement by a factor k

when 0 < k < 1, we have a reduction by a factor k

in this case, k = 1/3, then:

We have a reduction by a factor of 1/3

The correct option is:

"reduced by a factor of One-third."

7 0

3 years ago

Read 2 more answers

Select the functions that have identical graphs.

Elan Coil [88]

Answer:

c. 1 and 3

Step-by-step explanation:

To quickly solve this problem, we can use a graphing tool or a calculator to plot each equation.

Please see the attached image below, to find more information about the graph

The equations are:

1) y = sin (3x + π/6)

2) y = cos (3x - π/6)

3) y = cos (3x - π/3)

Looking at the graphs, we can see that the identical ones

are equations one and three

Correct option:

c. 1 and 3

3 0

4 years ago

I am trying to graduate HS please help me out!!!

vichka [17]

1. To solve this exercise, you must apply the formula for calculate the area of a trapezoid, which is shown below:

A=(b1+b2/2)h

A is the area of the trapezoid.
 b1 is the larger base of the trapezoid (b1=16-4=12 ft).
 b2 is the smaller base of the trapezoid (b2=10-4=6 ft).
 h is the height of the trapezoid (h=12-4=8 ft)

2. When you substitute these values into the formula A=(b1+b2/2)h, you obtain:

A=(b1+b2/2)h
 A=(12 ft+6 ft/2)(8 ft)
 A=9 ftx8ft
 A=72 ft²

3. The length of fencing is: a²=b²+c² a=√b²+c² a=√(8 ft)²+(6 ft)² a=10 ft Perimeter (Length of fencing)=12 ft+8 ft+6 ft+10 ft=36 ft

6 0

3 years ago

I really need answers asap please.

ale4655 [162]

We're told x=-5 and y=11 and asked to evaluate a few expressions. That just means substitute these values into the expressions and compute the exact numerical answer.

$4y-10x = 4(11) - 10(-5) = 44 + 50 = 94$