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3 years ago

ΔABC has vertices A(0,10), B(4,10), and C(-2,4).

Mathematics

1 answer:

laiz [17]3 years ago

8 0

A simple diagram will show you the intersection of altitudes is in the 2nd quadrant. It must have x-coordinate -2, as the altitude to the "base" y=10 must be the vertical line through (-2, 4).

The appropriate choice is ...

... C: (-2, 12)

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Help me please don't understand

Whitepunk [10]

It is A and B I think hope it helps

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3 years ago

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What whole number most closely estimates to <br><img src="https://tex.z-dn.net/?f=%20%5Csqrt%7B50%7D%20" id="TexFormula1" title=

zepelin [54]

Answer:

Step-by-step explanation:

since $\sqrt{50}>\sqrt{49}=7$

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3 years ago

The graph shows a proportional relationship between the cost of grapes, in dollars, and the number of pounds of grapes.

andreyandreev [35.5K]

Answer:

where is the picture

Step-by-step explanation:

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2 years ago

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Find the area of the regular polygon

Y_Kistochka [10]

Answer:

A = 374.123 ft^2

Step-by-step explanation:

First, lets calculate the perimeter:

Perimeter (p) = side length (s) * number of sides (n)

$p = s * n$

$p = 12 * 6$

$p = 72$

Next, lets find the apothem, which is the shortest length from any side to the middle. It's like the radius in a circle, but more complicated.

Apothem (a) = side length (s) / ( 2 * tan(180/number of sides (n)) )

$a = \frac{s}{2 * tan (\frac{180}{n} )}$

$a = \frac{12}{2 * tan (\frac{180}{6} )}$

$a = \frac{12}{2 * \frac{\sqrt{3} }{3}}$

$a = \frac{12}{\frac{2\sqrt{3} }{3}}$

$a = \frac{12*3}{2\sqrt{3}}$

$a = \frac{6*3}{\sqrt{3}}$

$a = \frac{18}{\sqrt{3}}$

Now, finally, to find the area of a regular polygon, we use the following equation:

Area (A) = ( apothem (a) * perimeter (p) ) / 2

$A = \frac{a * p}{2}$

$A = \frac{\frac{18}{\sqrt{3} } * 72}{2}$

$A = \frac{18}{\sqrt{3}} * 36$

$A = \frac{640}{\sqrt{3}}$

Turning into a decimal:

$A = 374.123 ft ^2$

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2 years ago

Explain the steps for dividing decimals. Write three or four sentences.

SVETLANKA909090 [29]

Answer:

Step-by-step explanation:

Move the decimal point in the divisor and dividend.

Turn the divisor (the number you’re dividing by) into a whole number by moving the decimal point all the way to the right. At the same time, move the decimal point in the dividend (the number you’re dividing) the same number of places to the right.

Place a decimal point in the quotient (the answer) directly above where the decimal point now appears in the dividend.

Divide as usual, being careful to line up the quotient properly so that the decimal point falls into place.

Line up each digit in the quotient just over the last digit in the dividend used in that cycle.

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3 years ago

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