All categories

3 years ago

Please help me answer this I don't understand, I would really appreciate how you solved it as well.

Mathematics

1 answer:

abruzzese [7]3 years ago

5 0

Answer: Parallel

Step-by-step explanation:

Set your -2x+10y=5 equation equal to y

-2x+10y=5

-10y -10y

-2x=5-10y

-5 -5

-2x-5+-10y

-10 -10 -10

-1/5x-1/2=y

Now you can put your equations into your graphing calculator and examine the lines made

(if you dont have one search up online graphing calculator on google or your app store)

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Write an equation that describes the function.

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The scatter plot shows the amount of sleep Aria got the night before a test and her test scores. Use the y-intercept, (0, 62), a

kotegsom [21]

Answer:

y = 3x + 62

Step-by-step explanation:

Trend line equation in the form :

y = mx + b

m = slope

b = intercept

Using the points :

(0, 62) ; (6, 80)

Slope, m = Rise / Run = (y2-y1) / (x2 - x1)

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3 0

3 years ago

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larisa86 [58]

Answer:

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Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

Help please! Will pick the Brainliest. (sorry if it’s sideways)

KatRina [158]

$(x^2y^8)^\frac{2}{3}=x^{2\cdot\frac{2}{3}}y^{8\cdot\frac{2}{3}}=x^{\frac{4}{3}}y^{\frac{16}{3}}=x^{1\frac{1}{3}}y^{5\frac{1}{3}}=x^1x^\frac{1}{3}y^5y^\frac{1}{3}=xy^5\sqrt[3]{x}\sqrt[3]{y}=\boxed{xy^5\sqrt[3]{xy}}$

Answer B)

$\frac{1}{3}\left(\frac{2}{15}x-\frac{2}{3}\right)>x+\frac{1}{5}\quad|\cdot3\\\\\\\frac{2}{15}x-\frac{2}{3}>3x+\frac{3}{5}\quad|\cdot15\\\\\\2x-\frac{30}{3}>45x+\frac{45}{5}\\\\2x-10>45x+9\\\\-10-9>45x-2x\\\\-19>43x\quad|:43\\\\\boxed{x$

Answer B)

$\sqrt{14xy}\cdot\sqrt{12}\cdot\sqrt{30y}=\sqrt{14\cdot12\cdot30}\cdot\sqrt{xy^2}=\sqrt{2\cdot7\cdot3\cdot4\cdot2\cdot3\cdot5}\cdot\sqrt{xy^2}=\\\\=\sqrt{2^2\cdot3^2\cdot2^2\cdot5\cdot7}\cdot\sqrt{xy^2}=2\cdot3\cdot2\cdot\sqrt{35}\cdot y\cdot\sqrt{x}=\boxed{12y\sqrt{35x}}$

3 0

4 years ago