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Ray Of Light [21]
4 years ago
8

Two right triangles are graphed on a coordinate plane. One triangle has a vertical side of 4 and a horizontal side of 10. The ot

her triangle has a vertical side of 12 and a horizontal side of 30.
Could the hypotenuses of these two triangles lie along the same line?
No, because they are not similar triangles
No, because one is larger than the other
Yes, because they are similar triangles
Yes, because they are both right triangles
Mathematics
1 answer:
Dahasolnce [82]4 years ago
4 0
They are similar triangles because they are both right triangles
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The x-y is the answer can someone please explain to me how to do
guapka [62]

Answer:

Step-by-step explanation:

\frac{\sqrt{x-y}}{\sqrt{x+y}-\sqrt{x-y}}-\frac{\sqrt{x-y}}{\sqrt{x+y}+\sqrt{x-y}}\\\\=\frac{\sqrt{x-y}*(\sqrt{x+y}+\sqrt{x-y})-(\sqrt{x-y})*(\sqrt{x+y}-\sqrt{x-y})}{(\sqrt{x+y}-\sqrt{x-y})*(\sqrt{x+y}+\sqrt{x-y})}\\\\=\frac{\sqrt{x-y}*(\sqrt{x+y}+\sqrt{x-y}-\sqrt{x+y}+\sqrt{x-y})}{(\sqrt{x+y})^2-(\sqrt{x-y)^{2}}}\\\\=\frac{\sqrt{x-y}*2\sqrt{x-y}}{x+y-x+y}\\\\=2*\frac{x-y}{2y}=\frac{x-y}{y}\\\\(\frac{\sqrt{x-y}}{\sqrt{x+y}-\sqrt{x-y}}-\frac{\sqrt{x-y}}{\sqrt{x+y}+\sqrt{x-y}})*y=\frac{x-y}{y}*y\\\\=x-y

4 0
4 years ago
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Mr. Jones drove 480 miles to a business meeting his travel time to the meeting was 8hours and from the meeting was 7.5 hours fin
Dmitry [639]
Speed = distance / time

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s = 480 / 8 = 60 miles per hr

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The equation below expresses the approximate
natka813 [3]

Answer:

The ball will be the 7 ft high at 2 different times.

Step-by-step explanation:

The height in meters of the ball is given by the following equation:

h(t) = -16t^2 + 25t

7 feet high

The height, by the equation, is given in meters, so we have to work in meters. Since each feet has 0,3048 meters, 7 feet have have 2.1336 meters. So, we have to solve the following equation

2,1336 = -16t^2 + 25t

16t^2 - 25t + 2,1336 = 0

At how many different times will the ball be 7 ft. High?

We have to find the number of solutions for the equation above.

It is given according to the value of \Delta = b^2 - 4ac. If it is positive, there are two solutions, zero one solution and negative no solutions.

In this equation a = 16, b = -25, c = 2.1336. So

\Delta = b^2 - 4ac = (-25)^2 - 4*16*2.1336 = 488

Since the coefficient is positive, the ball will be the 7 ft high at 2 different times.

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