Answer:
z = 10°
Step-by-step explanation:
Since the two sides are equal, the two base angles have to be equal
That means that 5z and 130 form a straight line and add to 180 degrees
5z+130 = 180
Subtract 130 from each side
5z = 50
Divide by 5
5z/5 = 50/5
z=10
Gg easey
perimiter is jsut the sum of the measures of the sides
P=2.3x+14+2x-0.2x+15
group like terms
P=2.3x+2x-0.2x+14+15
add
P=4.1x+29
answer is first one
_Award brainliest if helped!
(-5q * 3) + (4 *3 ) = -15q + 12
The answer is C.
Answer:
Answer options
A. Two cities that are 7.5 cm apart on the map are actually 50 km apart.
D. Two cities that are actually 66 km apart are 9.9 cm apart on the map.
Step-by-step explanation:
Step 1
Indicate the scale as shown;
3 cm : 20 km, meaning 3 cm on the map represents 20 km on the ground
A). what does 7.5 cm represent on the ground
Distance on ground=(7.5×20)/3=50 km
B). what does 4 cm represent on the ground
Distance on ground=(4×20)/3=26.67 km
C). what does 45 km on ground represent on the map
Distance on map=(45×3)/20=6.75 cm
D). what does 66 km on ground represent on the map
Distance on the map=(66×3)/20=9.9 cm
Step-by-step explanation:
Hey there!
The points of line AB are; (-1,-4) and (2,11).
Note:
- Use double point formula and simplify it to get two eqaution.
- Use condition of parallel lines, perpendicular lines to know whether the lines are parallel or perpendicular or nothing.
~ Use double point formula.

~ Keep all values.

~ Simplify it.



Therefore this is the equation of line AB.
Now, Finding the equation of line CD.
Given;
The points of line CD are; (1,1) and (4,10).
~ Using formula.

~ Keep all values.

~ Simplify it.


Therefore, 3x - y- 2 = 0 is the eqaution of line CD.
Use condition of parallel lines.
m1= m2
Slope of equation (i)


Therefore, m1 = 5
Slope of second equation.


Therefore, m2 = 3.
Now, m1≠m2.
So, the lies are not parallel.
Check for perpendicular.
m1*m2= -1
3*5≠-1.
Therefore, they aren't perpendicular too.
So, they are neither.
<em><u>Hope </u></em><em><u>it</u></em><em><u> helps</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em>