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Leviafan [203]
4 years ago
5

Find the percent using the percent equation. 238 cartons is what percent of 68 ​cartons?

Mathematics
1 answer:
stealth61 [152]4 years ago
6 0

Answer:

350%

Step-by-step explanation:

We can write an equation to represent the situation:

238 = x * 68

so,

238/68 = x

x = 3.5

convert that to a percent...

350% :)

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The answer is 53 because if you think about it
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4 years ago
PLEASE HELP WILL MARK BRAINLIEST!!!!!!!!
Hunter-Best [27]

The true statement is (a) segment BC is located at B (1, 0) and C (1, 3) and is one-half the size of segment B'C'

The coordinates are given as:

B'=(2,0)

C'=(2,6)

The scale factor from BC is given as:

k=2

So, the coordinates of segment BC are calculated using:

B'=B*k

C'=C*k

This gives

(2,0)=B*2

Divide both sides by 2

B=(1,0)

Also, we have:

(2,6)=C*2

Divide both sides by 2

C=(1,3)

Hence, the true statement is (a)

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brainly.com/question/3457976

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3 years ago
15/40 in its simplest form
marysya [2.9K]
Find the GCF (greatest common factor) which in this equation is 5. Divide both numbers by 5 and you'll get an answer of 3/8.
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4 years ago
Baxter is thinking about buying a car. The table below shows the projected value of two different cars for three years.
MAVERICK [17]

Answer:

A) car 1: exponential

   car 2: linear

B) car 1: f(x)=18500(0.94)^{x-1}

    car 2: f(x)=-1000x+19500

C) Yes, there will be a significant difference of $1,100.40 which is approx 10% of the value of the cars after 10 years.

Step-by-step explanation:

<u>Part A</u>

Car 1: exponential as the projected value is not decreasing by the same amount each year

Car 2: linear as the projected value decreases by the same amount each year ($1000)

<u>Part B</u>

<u>Car 1</u>

General form of exponential function: y=ab^x

a = initial value = 18500

b = growth factor = \dfrac{17390}{18500}=0.94

\implies f(x)=18500(0.94)^{x-1}

NB We have to change x to "x-1" since we are told in the table that <u>after</u> 1 year the car's value is 18500.

<u>Car 2</u>

General form of linear function:  y=mx+b

m=\dfrac{\textsf{change in} \ y}{\textsf{change in} \ x}=\dfrac{17500-18500}{2-1}=-1000

y-y_1=m(x-x_1)

\implies y-17500=-1000(x-2)

\implies f(x)=-1000x+19500

<u>Part C</u>

Car 1 after 10 years: \implies f(10)=18500(0.94)^{10-1}=\$10,600.40

Car 2 after 10 years: \implies f(10)=-1000(10)+19500=\$9,500

Difference = 10600.40 - 9500 = 1100.40

Yes, there will be a significant difference of $1,100.40 which is approx 10% of the value of the cars after 10 years.

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2 years ago
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I think the answer is: a score of <span>38 on a test for which = 27 and s = 10</span>
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