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Natalka [10]
3 years ago
13

Label each piece as FUNCTION or NOT A FUNCTION:

Mathematics
1 answer:
zavuch27 [327]3 years ago
5 0
Not sure about 5 and 8 however
6: Function. Every Y input has only 1 X input
7: Not a function
9: Not a function
10: Function
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write an equation that is perpendicular to x - 3y =3 and passes through the point (5,-9) in slope-intercept form.
Aleksandr [31]

9514 1404 393

Answer:

  y = -3x +6

Step-by-step explanation:

The perpendicular line will have the coefficients of x and y swapped (and one of them negated), and will have a constant appropriate to the point the line needs to go through.

The equation will look like ...

  x -3y = 3 . . . . . . . . . . . . . given line

  3x +y = constant . . . . . . perpendicular line

where "constant" can be found by substituting for x and y.

  3x +y = 3(5) +(-9)

  3x +y = 6 . . . . equation in standard form

To put this in slope-intercept form subtract 3x:

  y = -3x +6

6 0
3 years ago
Jackie has 1/3 of a Hershey bar.steven has 4/12 of a Hershey bar.How much do they have together?
Alisiya [41]
Since Jackie has 1/3 and Steven has 4/12 we add them together


4/12+1/3= 2/3

Together they have 2/3 of a Hershey Bar
8 0
3 years ago
Read 2 more answers
what is the equation of the line that passes through (-9,12) and is perpendicular to the line whose equation is y=1/3x+6
BabaBlast [244]
Y=kx+b
line is perpendicular y=1/3x+6⇒ k=-\frac{1}{ \frac{1}{3} }=-3

 so line y=-3x+a
 this line that passes through (-9,12)⇔x=-9, y=12, so 12=-3(-9)+a
12=27+a
a=12-27
a=-15
y=-3x-15

P.s.picture<span> to test solutions <span>in the application</span></span>


8 0
3 years ago
Read 2 more answers
sam had 70 erasers and rulers. after giving away 1/3 of his erasers and 10 rulers, he had an equal number of erasers and rulers
Radda [10]

Answer:

36 erasers

Step-by-step explanation:

Let number of erasers be e

let number of rulers be r

We can write:

e + r = 70

and

After giving away, he has

Erasers:  2/3e

Rulers:  r - 10

These two are equal, so we can write and solve:

2/3e = r - 10

2/3e + 10 = r

Putting this in initial equation, we have:

e + (2/3e + 10) = 70

5/3e + 10 = 70

5/3 e = 60

e = 36

And rulers is:

r = 2/3(36) + 10 = 34

Hence, he had 36 erasers in the beginning

4 0
3 years ago
One option in a roulette game is to bet $ 6
Eduardwww [97]

Answer:

<h2>We have 47% of chances to win those six bucks.</h2>

Step-by-step explanation:

In this problem we need to find the probabilty of winning thos $6.

According to the problem, we win $6 if we hit one red. We know that there are 18 red compartments, 18 black compartments and 2 neither red nor blakc, for a total of 38 compartments.

We need to use the standard probabilty definition which is the ratio between the number of events and the total number of outcomes. So,

P=\frac{18}{38} \approx 0.47

Which is equivalent to 47% of chances.

Therefore, we have 47% of chances to win those six bucks. (The Casino has the odds in their favor)

5 0
2 years ago
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