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vampirchik [111]
3 years ago
11

HELP ASAP The points A(4, 0) and B(3, 7) are two vertices of right triangle ABC . The hypotenuse of the triangle is AB¯¯¯¯¯ . Po

int C is on the x-axis What are the coordinates of point C? Enter your answers in the boxes.

Mathematics
2 answers:
Colt1911 [192]3 years ago
6 0

\text{Answer: The coordinates of C is }(3,0)

Explanation:

Since we have given that

A(4,0) and B(3,7) are two vertices of right triangle ABC.

The hypotenuse of the triangle is AB.

Construct a rectangle ABCD with AB as its diagonal ,

With the help of A(4,0) and B(3,7) we can find the coordinate of C ,

Since the x-coordinate of A and C will be same and the y-coordinate of B and C will be same ,

So, the coordinate of C becomes (3,0).

Similarly,

Since the x-coordinate of B and D and the y-coordinate of A and D will be same,

\text{So, the coordinates of D becomes (4,7) }

But From C and D we will choose  C as the third coordinate of Triangle because point C is on the x-axis.

\text{Hence, the coordinates of C is (3,0)}

ASHA 777 [7]3 years ago
5 0
If you draw a simple diagram you can see that point to form a right angle ACB, C must be at (3,0).
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Simplify (12a5−6a−10a3)−(10a−2a5−14a4) . Write the answer in standard form
almond37 [142]

Answer:

=14a^5+14a^4-10a^3-16a

Step-by-step explanation:

\left(12a^5-6a-10a^3\right)-\left(10a-2a^5-14a^4\right)\\\mathrm{Remove\:parentheses}:\quad \left(a\right)=a\\=12a^5-6a-10a^3-\left(10a-2a^5-14a^4\right)\\-\left(10a-2a^5-14a^4\right):\quad -10a+2a^5+14a^4\\-\left(10a-2a^5-14a^4\right)\\\mathrm{Distribute\:parentheses}\\=-\left(10a\right)-\left(-2a^5\right)-\left(-14a^4\right)\\Apply\:minus-plus\:rules\\-\left(-a\right)=a,\:\:\:-\left(a\right)=-a\\=-10a+2a^5+14a^4\\=12a^5-6a-10a^3-10a+2a^5+14a^4

\mathrm{Simplify}\:12a^5-6a-10a^3-10a+2a^5+14a^4:\quad 14a^5+14a^4-10a^3-16a12a^5-6a-10a^3-10a+2a^5+14a^4\\Group\:like\:terms\\=12a^5+2a^5+14a^4-10a^3-6a-10a\\\mathrm{Add\:similar\:elements:}\:12a^5+2a^5=14a^5\\=14a^5+14a^4-10a^3-6a-10a\\\mathrm{Add\:similar\:elements:}\:-6a-10a=-16a\\=14a^5+14a^4-10a^3-16a

4 0
3 years ago
We have a study involving 5 different groups that each contain 9 participants (45 total). What two degrees of freedom would we r
vivado [14]

Answer:

Degree of freedoms F(4,40)

Step-by-step explanation:

Given:

There is a study which is involving 5 different groups that each contains 9 participants (totally 45)

The objective is to calculate the degree of freedoms

Formula used:

Numerator degree of freedom = k-1

denominator degree of freedom=N-K

Solution:

Numerator degree of freedom = k-1

denominator degree of freedom=N-K

Where,

K= number of groups = 5

N= total number of observations

which is given as follows,

N=45

Then,

Numerator degree of freedom = k-1

=5-1

=4

Denominator degree of freedom = N-K

=45-5

=40

Therefore,

Degree of freedoms, F(4,40)

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3 years ago
A tent rental company charges a mandatory $125 setup fee and a $90 hourly rental fee. Which of the following equations can be us
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If triangle STU  ≅ triangle ABC, then ∠T ≅ ∠B, ∠S ≅ ∠A, and segment TU ≅ Segment BC are true by CPCTC. Option A, option B, and option D are correct.

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triangle STU  ≅ triangle ABC

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To learn more about the congruence of the triangle visit:

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Answer:

7

Step-by-step explanation:

Its 7 because khan academy and i know it

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