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The inclination to the nearest tenth of a degree exists 0.24146
<h3>What is the inclination to the nearest tenth of a degree?</h3>
The given scenario includes a right-angled triangle where the length of the ramp exists hypotenuse and the rise of ramp exists the perpendicular.
Given: H = 4.6 m and P = 1.1 m
We have to use the trigonometric ratios to find the angle. The ratio that has to be used should involve both perpendicular and hypotenuse
Let x be the angle then
sin x = P/H
sin x = 1.1/4.6
sin x = 0.23913
= 0.24146
The inclination to the nearest tenth of a degree exists 0.24146
To learn more about trigonometric ratios refer to:
brainly.com/question/14033725
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Answer:
y = 2/3x - 3
Step-by-step explanation:
Step 1: Write equation
2x - 3y = 9
Step 2: Solve for <em>y</em>
- Subtract 2x on both sides: -3y = 9 - 2x
- Divide both sides by -3: y = -3 + 2/3x
- Rewrite: y = 2/3x - 3