Question

PLEASEEEEEEEE HELP

Answer 1

Answer:

Using the point-slope form:

The equation of the line is given by:

$y-y_1 =m(x-x_1)$ .....[1]  where

m is the slope of the line and $(x_1, y_1)$ is the point on the line.

As per the statement:

Given: Two points i,e (34, 76) and (42, 91)

First calculate slope(m):

Slope is given by:

$\text{Slope} = \frac{y_2-y_1}{x_2-x_1}$

Substitute the given values we have;

$\text{Slope (m)} = \frac{91-76}{42-34}=\frac{15}{8}=1.875$

Now, substitute the value of m and (34, 76) in [1] we have;

$y-76 =1.875(x-34)$

Using distributive property: $a \cdot (b+c) = a\cdot b+ a\cdot c$

$y-76 =1.875x-63.75$

Add 76 to both sides we get;

$y=1.875x+76$

Therefore, the equation of the trend line is: $y=1.875x+76$

Answer 2

Answer:

The equation of the trend line is $y=1.875x+12.25$.

Step-by-step explanation:

Given : The points (34,76) (42,91).

To find : The equation of the trend line (line of best fit) ?

Solution :

Using two point slope form to find the equation of line.

$(y-y_1)=(\frac{y_2-y_1}{x_2-x_1})(x-x_1)$

Here, $(x_1,y_1)=(34,76)$ and $(x_2,y_2)=(42,91)$

Substitute the value,

$(y-76)=(\frac{91-76}{42-34})(x-34)$

$(y-76)=(\frac{15}{8})(x-34)$

$(y-76)=\frac{15}{8}x-\frac{15}{8}\times 34$

$(y-76)=1.875x-63.75$

$y=1.875x-63.75+76$

$y=1.875x+12.25$

Therefore, the equation of the trend line is $y=1.875x+12.25$.