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ki77a [65]
3 years ago
9

PLEASEEEEEEEE HELP

Mathematics
2 answers:
Rama09 [41]3 years ago
8 0

Answer:

Using the point-slope form:

The equation of the line is given by:

y-y_1 =m(x-x_1) .....[1]  where

m is the slope of the line and (x_1, y_1) is the point on the line.

As per the statement:

Given: Two points i,e (34, 76) and (42, 91)

First calculate slope(m):

Slope is given by:

\text{Slope} = \frac{y_2-y_1}{x_2-x_1}

Substitute the given values we have;

\text{Slope (m)} = \frac{91-76}{42-34}=\frac{15}{8}=1.875

Now, substitute the value of m and (34, 76) in [1] we have;

y-76 =1.875(x-34)

Using distributive property: a \cdot (b+c) = a\cdot b+ a\cdot c

y-76 =1.875x-63.75

Add 76 to both sides we get;

y=1.875x+76

Therefore, the equation of the trend line is: y=1.875x+76

OLga [1]3 years ago
7 0

Answer:

The equation of the trend line is y=1.875x+12.25.

Step-by-step explanation:

Given : The points (34,76) (42,91).

To find : The equation of the trend line (line of best fit) ?

Solution :

Using two point slope form to find the equation of line.

(y-y_1)=(\frac{y_2-y_1}{x_2-x_1})(x-x_1)

Here, (x_1,y_1)=(34,76) and (x_2,y_2)=(42,91)

Substitute the value,

(y-76)=(\frac{91-76}{42-34})(x-34)

(y-76)=(\frac{15}{8})(x-34)

(y-76)=\frac{15}{8}x-\frac{15}{8}\times 34

(y-76)=1.875x-63.75

y=1.875x-63.75+76

y=1.875x+12.25

Therefore, the equation of the trend line is y=1.875x+12.25.

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