that log4x=2log16x. (ii)Show that log x=3logb³ x. (iii) Show that log₂x=(1+log₂3)logix
6/7 divide by 3/14
Divide = multiply reciprocal
6/7 * 14/3 = 84/21 = 4
She can paint 4 pictures in a full hour
5.98/.32 is 18.6875
so rounded would be 18.7 times
Answer:
We know that In 1990, the mean duration of long-distance telephone calls originating in one town was 7.2 minutes. And we want to test if the mean duration of long-distance phone calls has changed from the 1990 mean of 7.2 minutes (alternative hypothesis) and the complement rule would represent the null hypothesis.
The correct system of hypothesis are:
Null hypothesis: 
Alternative hypothesis: 
So then the best option for this case would be:
H0: μ = 7.2 minutes Ha: μ ≠ 7.2 minutes
Step-by-step explanation:
We know that In 1990, the mean duration of long-distance telephone calls originating in one town was 7.2 minutes. And we want to test if the mean duration of long-distance phone calls has changed from the 1990 mean of 7.2 minutes (alternative hypothesis) and the complement rule would represent the null hypothesis.
The correct system of hypothesis are:
Null hypothesis: 
Alternative hypothesis: 
So then the best option for this case would be:
H0: μ = 7.2 minutes Ha: μ ≠ 7.2 minutes
And in order to test the hypothesis we can use a one sample t test or z test depending if we know the population deviation or not
Answer:
a)

For any integer k between 0 and 15, and 0 for other values of k.
b)

c) P(6 ≤ X ≤ 10) = 0.2737
d) μ = 15*0.75 = 11.25. σ² = 11.25*0.25 = 2.8125
Step-by-step explanation:
X is a binomial random variable with parameters n = 15, p = 0.75. Therefore
a)

For any integer k between 0 and 15, and 0 for other values of k.
b)
P(X>10) = P(X=11) + P(X=12)+ P(X=13)+P(X=14)+P(x=15)





Thus,

c) P(6 ≤ X ≤ 10) = P(X = 6) + P(X = 7) + P(X = 8) + P(X=9) + P(X=10)





Thereofre,

d) μ = n*p = 15*0.75 = 11.25
σ² = np(1-p) = 11.25*0.25 = 2.8125