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3 years ago

Please help!!!!!!!!!!!!!

Mathematics

1 answer:

Yuri [45]3 years ago

8 0

Answer:

37, 3, 37

Step-by-step explanation:

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Find the slope of the line tangent to the graph of y = sin- 1 x at<br> x = 0.

Anastasy [175]

Answer:

Step-by-step explanation:

First find the derivative of sin-1x.

This is a standard derivative and it is 1 /√(1 - x^2)

This is the slope of the graph at x.

Slope at x = 0 = 1 /√(1 - 0^2)

= 1/1 = 1,

6 0

3 years ago

Which of the following statements is false regarding randomization?

Tanzania [10]

Answer:

Step-by-step explanation:

the other person is wrong

4 0

3 years ago

Helppp Plsss Asap!! Thanks!!

LenKa [72]

the answer is 12 because if you look at the position of the y axis when x equals 2 then look at the y value when x equals 4 you will get the 2 numbers 4 and 16 now subtract 16 by 4 and you get 12.

8 0

3 years ago

Read 2 more answers

4) Find the value of x in the given diagram. (3 points)

Oxana [17]

Answer:

113

Step-by-step explanation:

The given shape has 6 angles so it's a hexagon and the sum of interior angles in a hexagon is = 720

To find the the value of x we need to add all given values up and subtract it from 720:

88 + 142 + 105 + 136 + 136 + x = 720

607 + x = 720 subtract 607 from both sides

x = 113

3 0

2 years ago

Find the general solution of the following equation. Express the solution explicitly as a function of the independent variable.

Mashcka [7]

Answer:

Therefore the general solution is

$2 \sqrt w = 2 ln(x) - 5 \frac1x +c$

Step-by-step explanation:

Integration Rule:

$\int x^n dx= \frac{x^{n+1}}{n+1}+c$
$\int \frac1x dx= ln(x) +c$

Given differential equation is

$x^2 \frac{dw}{dx}= \sqrt{w}(2x+5)$

$\Rightarrow x^2 dw= \sqrt{w} (2x+5) dx$ [ multiplying dx both sides]

$\Rightarrow \frac{dw}{\sqrt w}= \frac{(2x+5)}{x^2} dx$ [ dividing $x^2\sqrt w$ both sides]

Integrating both sides

$\int \frac{dw}{\sqrt w}=\int \frac{(2x+5)}{x^2} dx$

$\Rightarrow \int w^{-\frac12} dw=\int (\frac{2x}{x^2}+\frac{5}{x^2} )dx$

$\Rightarrow \int w^{-\frac12} dw=\int \frac{2}{x}dx +\int\frac{5}{x^2} dx$

$\Rightarrow \frac{w^{-\frac12+1}}{-\frac12+1} =2ln x+5 \frac{x^{-2+1}}{-2+1}+c$ [ c is arbitrary constant]

$\Rightarrow 2 \sqrt w = 2 ln(x) - 5 \frac1x +c$

Therefore the general solution is

$2 \sqrt w = 2 ln(x) - 5 \frac1x +c$

6 0

3 years ago