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Dominik [7]
3 years ago
5

Probability math help! Please help :)

Mathematics
1 answer:
sukhopar [10]3 years ago
7 0

Answer:

20%

Step-by-step explanation:

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Which of the following has the lowest unit price?
saw5 [17]
The answer is c . 24ib for $18.72
3 0
3 years ago
The graph below shows the number of open blossoms in a nursery and the number of hours after dawn. answer all that apply
uysha [10]

Answer:

The correct option is B.

Step-by-step explanation:

The given equation is

y=20x+3

This equation represent the number of open blossoms in a nursery after x hours.

At initial the number hours is 0.

Substitute x=0 in the given equation.

y=20(0)+3

y=0+3

y=3

The initial value is 3, it means there were three blossoms open at dawn. Option B is correct.

6 0
3 years ago
How to know if a function is periodic without graphing it ?
zhenek [66]
A function f(t) is periodic if there is some constant k such that f(t+k)=f(k) for all t in the domain of f(t). Then k is the "period" of f(t).

Example:

If f(x)=\sin x, then we have \sin(x+2\pi)=\sin x\cos2\pi+\cos x\sin2\pi=\sin x, and so \sin x is periodic with period 2\pi.

It gets a bit more complicated for a function like yours. We're looking for k such that

\pi\sin\left(\dfrac\pi2(t+k)\right)+1.8\cos\left(\dfrac{7\pi}5(t+k)\right)=\pi\sin\dfrac{\pi t}2+1.8\cos\dfrac{7\pi t}5

Expanding on the left, you have

\pi\sin\dfrac{\pi t}2\cos\dfrac{k\pi}2+\pi\cos\dfrac{\pi t}2\sin\dfrac{k\pi}2

and

1.8\cos\dfrac{7\pi t}5\cos\dfrac{7k\pi}5-1.8\sin\dfrac{7\pi t}5\sin\dfrac{7k\pi}5

It follows that the following must be satisfied:

\begin{cases}\cos\dfrac{k\pi}2=1\\\\\sin\dfrac{k\pi}2=0\\\\\cos\dfrac{7k\pi}5=1\\\\\sin\dfrac{7k\pi}5=0\end{cases}

The first two equations are satisfied whenever k\in\{0,\pm4,\pm8,\ldots\}, or more generally, when k=4n and n\in\mathbb Z (i.e. any multiple of 4).

The second two are satisfied whenever k\in\left\{0,\pm\dfrac{10}7,\pm\dfrac{20}7,\ldots\right\}, and more generally when k=\dfrac{10n}7 with n\in\mathbb Z (any multiple of 10/7).

It then follows that all four equations will be satisfied whenever the two sets above intersect. This happens when k is any common multiple of 4 and 10/7. The least positive one would be 20, which means the period for your function is 20.

Let's verify:

\sin\left(\dfrac\pi2(t+20)\right)=\sin\dfrac{\pi t}2\underbrace{\cos10\pi}_1+\cos\dfrac{\pi t}2\underbrace{\sin10\pi}_0=\sin\dfrac{\pi t}2

\cos\left(\dfrac{7\pi}5(t+20)\right)=\cos\dfrac{7\pi t}5\underbrace{\cos28\pi}_1-\sin\dfrac{7\pi t}5\underbrace{\sin28\pi}_0=\cos\dfrac{7\pi t}5

More generally, it can be shown that

f(t)=\displaystyle\sum_{i=1}^n(a_i\sin(b_it)+c_i\cos(d_it))

is periodic with period \mbox{lcm}(b_1,\ldots,b_n,d_1,\ldots,d_n).
4 0
3 years ago
What is the factored form of the expression?Factor completely. 6x^4-9x^3-36x^2+54x
mario62 [17]
If we factorize the expression

6x^4-9x^3-36x^2+54x

We will get

3x(2x-3)(x^2-6)


Hope I helped!
8 0
3 years ago
Read 2 more answers
Which ordered pair is a solution of the equation y = 4x - 3?
Greeley [361]

Answer:

(0,-3)

(1,1)

(2,5)

Step-by-step explanation:

They're all correct. it doesn't matter which one you choose.

3 0
3 years ago
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