Answer:
7
Step-by-step explanation:
I just want points
Answer: e = 17.8
Step-by-step explanation: 14.6 + 3.2
Answer:
The second time when Luiza reaches a height of 1.2 m = 2 08 s
Step-by-step explanation:
Complete Question
Luiza is jumping on a trampoline. Ht models her distance above the ground (in m) t seconds after she starts jumping. Here, the angle is entered in radians.
H(t) = -0.6 cos (2pi/2.5)t + 1.5.
What is the second time when Luiza reaches a height of 1.2 m? Round your final answer to the nearest hundredth of a second.
Solution
Luiza is jumping on trampolines and her height above the levelled ground at any time, t, is given as
H(t) = -0.6cos(2π/2.5)t + 1.5
What is t when H = 1.2 m
1.2 = -0.6cos(2π/2.5)t + 1.5
0.6cos(2π/2.5)t = 1.2 - 1.5 = -0.3
Cos (2π/2.5)t = (0.3/0.6) = 0.5
Note that in radians,
Cos (π/3) = 0.5
This is the first time, the second time that cos θ = 0.5 is in the fourth quadrant,
Cos (5π/3) = 0.5
So,
Cos (2π/2.5)t = Cos (5π/3)
(2π/2.5)t = (5π/3)
(2/2.5) × t = (5/3)
t = (5/3) × (2.5/2) = 2.0833333 = 2.08 s to the neareast hundredth of a second.
Hope this Helps!!!
Answer:
The jellyfish travels faster than the walrus
Step-by-step explanation:
Given data
A jellyfish travels 3/5 mile in 1/6 hour
Distance= 3/5 mile
time= 1/6 hour
speed= distance/time
speed= 3/5/1/6
speed= 3/5*6/1
speed= 18 mile per hour
a walrus travels 5/6 mile in 3/10 hour.
Distance= 5/6 mile
time= 3/10 hour.
speed= distance/time
speed= 5/6/3/10
speed= 5/6*10/3
speed= 50/18 mile per hour
12.4 because 62 divided by 5 = 12.4
