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ololo11 [35]
3 years ago
6

Find the product of f(x)=3 and g(x)=x+7

Mathematics
1 answer:
DaniilM [7]3 years ago
8 0
F(x)=3 domain: negative infinity, positive infinity range: 3

g(x)=x+7 domain: - infinity, + infinity range: - infinity, + infinity
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Jimmy has listed the amount of money in his wallet for each of the last ten days. He decides to remove day 7, as that was payday
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Answer:

The mean will reduce

Step-by-step explanation:

The total amount of money for the ten days divided by number of days will give mean 1, M₁

Removing the value for day seven will reduce the sum of money as it will be for 9 days only.In finding the mean, you will divide by 9 days to get mean M₂

Mean M₂ < M₁

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The price for 12 muffins is $10.00

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Which values of a and b make the equation true
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I really need help with this question
Step2247 [10]

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option (b) -3(3w-3.1)

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Read 2 more answers
Need Help! I don't get it
serious [3.7K]
Well hmmm let's say you take the car and go in the city for 60 miles with it, well, the car can do 60 miles per gallon, since you just drove it for 60 miles, you only spent 1 gallon of gasoline then.

that only happens if you drive it for 60 miles, what if you drive it for more, let's do a quick table on that,

\bf \begin{array}{ccll}&#10;miles&cost\\&#10;\text{\textemdash\textemdash\textemdash}&\text{\textemdash\textemdash\textemdash}\\&#10;60&3.6(1)\\\\&#10;&3.6\left( \frac{60}{60} \right)\\\\&#10;120&3.6(2)\\\\&#10;&3.6\left( \frac{120}{60} \right)\\\\&#10;180&3.6(3)\\\\&#10;&3.6\left( \frac{180}{60} \right)&#10;\end{array}

and so on, now let's check if you less than 60 miles,

\bf \begin{array}{ccll}&#10;miles&cost\\&#10;\text{\textemdash\textemdash\textemdash}&\text{\textemdash\textemdash\textemdash}\\&#10;40&3.6\left( \frac{40}{60} \right)\\\\&#10;20&3.6\left( \frac{20}{60} \right)\\\\&#10;10&3.6\left( \frac{10}{60} \right)&#10;\end{array}

so, if you divide the amount of miles driven, by 60, when you have driven it for 120 miles, 120/60 is just 2, and the cost is for 2 gallons, or 3.6 * 2, which is 7.2 bucks, for 180 miles is 180/60 or 3 gallons for 3.6 * 3 bucks, and so on.

now, what if you drive it instead for "m" miles?

\bf \begin{array}{ccll}&#10;miles&cost\\&#10;\text{\textemdash\textemdash\textemdash}&\text{\textemdash\textemdash\textemdash}\\&#10;m&3.6\left( \frac{m}{60} \right)\\\\&#10;\end{array}\implies c=3.6\left( \cfrac{m}{60} \right)\implies c=\cfrac{3.6m}{60}&#10;\\\\\\&#10;c=\cfrac{3.6}{60}m\implies c=0.06m
3 0
3 years ago
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