1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
ololo11 [35]
3 years ago
6

Find the product of f(x)=3 and g(x)=x+7

Mathematics
1 answer:
DaniilM [7]3 years ago
8 0
F(x)=3 domain: negative infinity, positive infinity range: 3

g(x)=x+7 domain: - infinity, + infinity range: - infinity, + infinity
You might be interested in
Mr.Davis's students were surveyed on their favorite subject. One fifth prefer math, 0.35 prefer social studies, and 45% prefer r
lara [203]

its already in order


7 0
3 years ago
Read 2 more answers
Which of the following is not a property of a chi-square distribution?
laiz [17]

Answer:

c) Is not a property (hence (d) is not either)

Step-by-step explanation:

Remember that the chi square distribution with k degrees of freedom has this formula

\chi_k^2 = \matchal{N}_1^2 +  \matchal{N}_2^2 + ... + \, \matchal{N}_{k-1}^2 +  \matchal{N}_k^2

Where N₁ , N₂m .... N_k are independent random variables with standard normal distribution. Since it is a sum of squares, then the chi square distribution cant take negative values, thus (c) is not true as property. Therefore, (d) cant be true either.

Since the chi square is a sum of squares of a symmetrical random variable, it is skewed to the right (values with big absolute value, either positive or negative, will represent a big weight for the graph that is not compensated with values near 0). This shows that (a) is true

The more degrees of freedom the chi square has, the less skewed to the right it is, up to the point of being almost symmetrical for high values of k. In fact, the Central Limit Theorem states that a chi sqare with n degrees of freedom, with n big, will have a distribution approximate to a Normal distribution, therefore, it is not very skewed for high values of n. As a conclusion, the shape of the distribution changes when the degrees of freedom increase, because the distribution is more symmetrical the higher the degrees of freedom are. Thus, (b) is true.

6 0
3 years ago
Peter Piper bought 5 pickled pepper plants. Each plant cost $110. He also needed a
marysya [2.9K]

Answer:

6.75

Step-by-step explanation:

10.00-3.25= 5.75

the first pieces of information are irrelevant

7 0
3 years ago
What is the solution to the inequality 28 > 4 – 2p?
Schach [20]

Answer:

-12 < p

Step-by-step explanation:

28 > 4 – 2p

Subtract 4 from each side

28-4 > 4-4 – 2p

24 > -2p

Divide each side by -2, remembering to flip the inequality

24/-2 < -2p/-2

-12 < p

4 0
3 years ago
When designing a building, you must be sure that the building can withstand hurricane force winds, which have a velocity of 73mi
Vesnalui [34]

Answer- 42646.50 pounds


Area of flat surface = Area of rectangle + area of triangle

                                = 12.9*25 + 1/2* 7.2* 25

                                 = 162.5 feet^2

Force exerted by wind =0 .004 * Area * velocity^2

                                      = 42646.50 pounds

5 0
3 years ago
Other questions:
  • 3-(x-3)=25 solve the equation
    10·1 answer
  • Mc Donald’s sells about 150 hamburgers every 3 seconds. How many seconds will it take to sell 6,400 hamburgers?
    10·1 answer
  • Help me PLEASEEEEEEEEEEEEE
    11·1 answer
  • −2x=x^2 −6 from khan academy helppppppp please
    15·1 answer
  • If I sell shirts for $15 a piece plus a a shipping fee of $20, what would my slope be?
    10·2 answers
  • 1+1
    10·2 answers
  • 7th grade | discover the pattern and continue
    9·1 answer
  • Lines AD and BC are parallel. Find the measures
    10·1 answer
  • Anyone mind helpingg?
    5·1 answer
  • 1. An account is opened with a balance of $2800earning 4.25% simple interest. What will be thebalance in the account in 30 years
    9·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!