The answer is 52 hopefully this help
Answer:
5 kg
Step-by-step explanation:
To solve this problem, we can use the rule of three.
In fact, we know that:
- 1 kilogram is equivalent to 2.2 pounds
- The ratio between the mass in kilograms and in pounds is constant for every value of the mass
- Therefore, the mass in kilograms corresponding to 11 pounds can be found by writing the following equation:

Where
x is the mass in kilograms corresponding to 11 pounds.
Solving the equation for x, we find:

Answer:
f(-2) = 21
Step-by-step explanation:
Step 1: Define
f(x) = 3x² - 4x + 1
f(-2) is x = -2
Step 2: Substitute and Evaluate
f(-2) = 3(-2)² - 4(-2) + 1
f(-2) = 3(4) + 8 + 1
f(-2) = 12 + 9
f(-2) = 21
the solid is made up of 2 regular octagons, 8 sides, joined up by 8 rectangles, one on each side towards the other octagonal face.
from the figure, we can see that the apothem is 5 for the octagons, and since each side is 3 cm long, the perimeter of one octagon is 3*8 = 24.
the standing up sides are simply rectangles of 8x3.
if we can just get the area of all those ten figures, and sum them up, that'd be the area of the solid.
![\bf \textit{area of a regular polygon}\\\\ A=\cfrac{1}{2}ap~~ \begin{cases} a=apothem\\ p=perimeter\\[-0.5em] \hrulefill\\ a=5\\ p=24 \end{cases}\implies A=\cfrac{1}{2}(5)(24)\implies \stackrel{\textit{just for one octagon}}{A=60} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ \stackrel{\textit{two octagon's area}}{2(60)}~~+~~\stackrel{\textit{eight rectangle's area}}{8(3\cdot 8)}\implies 120+192\implies 312](https://tex.z-dn.net/?f=%5Cbf%20%5Ctextit%7Barea%20of%20a%20regular%20polygon%7D%5C%5C%5C%5C%20A%3D%5Ccfrac%7B1%7D%7B2%7Dap~~%20%5Cbegin%7Bcases%7D%20a%3Dapothem%5C%5C%20p%3Dperimeter%5C%5C%5B-0.5em%5D%20%5Chrulefill%5C%5C%20a%3D5%5C%5C%20p%3D24%20%5Cend%7Bcases%7D%5Cimplies%20A%3D%5Ccfrac%7B1%7D%7B2%7D%285%29%2824%29%5Cimplies%20%5Cstackrel%7B%5Ctextit%7Bjust%20for%20one%20octagon%7D%7D%7BA%3D60%7D%20%5C%5C%5C%5C%5B-0.35em%5D%20%5Crule%7B34em%7D%7B0.25pt%7D%5C%5C%5C%5C%20%5Cstackrel%7B%5Ctextit%7Btwo%20octagon%27s%20area%7D%7D%7B2%2860%29%7D~~%2B~~%5Cstackrel%7B%5Ctextit%7Beight%20rectangle%27s%20area%7D%7D%7B8%283%5Ccdot%208%29%7D%5Cimplies%20120%2B192%5Cimplies%20312)
Circumference of circle = 11.27π ft
so,
C = 2πr
or, 11.27π = 2πr
or, 11.27π/2π = r
so, r = 5.635 ft
now,
diameter = 2r
= 2 x 5.635
= 11.27 ft