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ArbitrLikvidat [17]
3 years ago
10

What is the equation of a line through point (0,5) that is parallel to the line with equation y= x -7

Mathematics
1 answer:
e-lub [12.9K]3 years ago
4 0

Answer:

y=x+5

Step-by-step explanation:

Lines are parallel if they have the same slope, the Y-intercept does not matter. Since these line passes through point (0,5) it's y-intercept has to be 5 and It's still parallel with line y=x-7.

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Answer:WHOO!!

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A taxi company charges a $2.00 base fare plus an additional fare based on a per-mile rate and a per-minute rate. Ryan's first ta
Fed [463]

A $2.00 base fare charge, and per-mile, and per-minute rates related as follows; 3•x + 7•y = 6.5 and 7•x + 14•y = 14, give the distance traveled in the third ride as 4.5 miles

<h3>How can the length of the third ride be calculated?</h3>

The base fare = $2.00

Let <em>x </em>represent the per-mile rate, and let <em>y </em>represent the per-minute rate, we have;

The cost of Ryan's first taxi ride = $8.50

Distance traveled in the first ride = 3.0 miles

Time taken during the first ride = 7 minutes

Therefore;

2 + 3•x + 7•y = 8.5

Which gives;

3•x + 7•y = 8.5 - 2 = 6.5

  • 3•x + 7•y = 6.5...(1)

Distance traveled in the second ride = 7.0 miles

Duration of the second ride = 14 minutes

The second ride cost = $16.00

Therefore;

2 + 7•x + 14•y = 16

Which gives;

7•x + 14•y = 16 - 2 = 14

  • 7•x + 14•y = 14...(2)

Solving the above simultaneous equations by multiplying equation (1) by 2 then subtracting the result from equation (2) gives;

(7•x + 14•y) - 2 × (3•x + 7•y) = 14 - 2×6.5 = 1

x = 1

  • The per-mile rate, <em>x </em>= $1

3•x + 7•y = 6.5

7•y = 6.5 - 3•x

7•y = 6.5 - 3×1 = 3.5

y = 3.5/7 = 1/2 = 0.5

  • The per-minute rate, <em>y </em>= $0.5

Duration of the third taxi ride = 10 minutes

Cost of the third ride = $13.50

Therefore;

2 + 1×a + 10×y = $13.50

Where <em>a </em>is the distance traveled during the third ride, we have;

2 + 1×a + 10×0.5 = $13.50

2 + a + 5 = 13.5

a = 13.5 - 2 - 7 = 4.5

  • The third ride was, <em>a </em>= 4.5 miles

Learn more about simultaneous linear equations here:

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3 0
2 years ago
Dustin has a bag of marbles with 4 blue marbles, 4 white marbles, and 3 red marbles.
diamong [38]

Answer:

A.

\dfrac{6}{55}

B.

\dfrac{6}{55}

C.

\dfrac{4}{165}

Step-by-step explanation:

Dustin has a bag of marbles with 4 blue marbles, 4 white marbles, and 3 red marbles. There are 11 marbles in total.

A. The probability that the first marble drawn is blue marble is

\dfrac{4}{11},

the probability that the second marble drawn is red marble is

\dfrac{3}{10}

The probability that the first marble drawn is blue and the second is red is

\dfrac{4}{11}\cdot \dfrac{3}{10}=\dfrac{12}{110}=\dfrac{6}{55}

B. The probability that the first marble drawn is red marble is

\dfrac{3}{11},

the probability that the second marble drawn is white marble is

\dfrac{4}{10}

The probability that the first marble drawn is red and the second is white is

\dfrac{3}{11}\cdot \dfrac{4}{10}=\dfrac{12}{110}=\dfrac{6}{55}

C. The probability that the first marble drawn is blue marble is

\dfrac{4}{11},

the probability that the second marble drawn is blue marble is

\dfrac{3}{10},

the probability that the third marble drawn is blue marble is

\dfrac{2}{9},

The probability that the first, second and third marbles drawn are blue is

\dfrac{4}{11}\cdot \dfrac{3}{10}\cdot \dfrac{2}{9}=\dfrac{24}{990}=\dfrac{4}{165}

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3 years ago
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