PLEASE HELP MATH!!!1
1 answer:
The y< -2x + 6 is the one that crosses at 6 on the y-axis. the < indicates that you shade BELOW it, so the left side of that line is shaded because it has a negative slope.
the y> 5/4x - 6 is the one that crosses at -6 on the y-axis. the > indicates that you shade ABOVE it, so the left side would also be shaded because it has a positive slope.
so whatever point is in both of those shaded areas would satisfy both inequalities
the y> 5/4x - 6 is the one that crosses at -6 on the y-axis. the > indicates that you shade ABOVE it, so the left side would also be shaded because it has a positive slope.
so whatever point is in both of those shaded areas would satisfy both inequalities
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Answer:
1) La serie geométrica formada es
4, 2, 1,..., ∞
2) La suma al infinito de las áreas de los cuadrados es 8 in.²
Step-by-step explanation:
1) El área del primer cuadrado, a₁ = 2² = 4 pulgadas²
El área del siguiente cuadrado, a₂ = (√ (1² + 1²)) ² = (√2) ² = 2 pulg²
El área del siguiente cuadrado, a₃ = ((√ (2) / 2) ² + (√ (2) / 2) ²) = 1 pulg²
Por lo tanto, la razón común, r = a₂ / a₁ = 2/4 = a₃ / a₂ = 1/2
Las áreas de los cuadrados progresivos forman una progresión geométrica como sigue;
4, 4×(1/2), 4 ×(1/2)²,...,4×
De donde obtenemos la serie geométrica formada de la siguiente manera;
4, 2, 1,..., ∞
2) La suma de 'n' términos de una progresión geométrica hasta el infinito para -1 <r <1 se da como sigue;
Por lo tanto, la suma de las áreas de los cuadrados hasta el infinito se obtiene sustituyendo los valores de 'a' y 'r' en la ecuación anterior de la siguiente manera;
La suma al infinito de las áreas de los cuadrados, = 8 in.²
Answer:
Circumference of a circle=
Step-by-step explanation:
The circumference of any circle is the total length of its boundary which can be calculated by the formula:
Circumference of a circle=
Where 'r' is the radius of the circle
For, the given circle the circumference can be find in terms of by putting some value of radius in the formula, which gives the circumference in terms of
.