Question

Two 2 1/2 inch plastic strips and two 5 1/3 inch plastic strips are used to form a rectangle. What is the perimeter of the rectangle?

Answer 1

In this question the given information's should be closely noted. The length and width of the perimeter are already given. Based on those information's the answer to the question can be easily deduced.
Length of the rectangle = 2 1/2 inch
                                       = 5/2 inch
Width of the rectangle = 5 1/3 inch
                                         = 16/3 inch
Then
Perimeter of a rectangle = 2 ( Length + Width)
                                        = 2 [(5/2) + (16/3)]
                                         = 2 [ (45 + 32)/6]
                                         = 2 * (77/6)
                                         = 77/3 inch
                                         = 25 2/3 inch
So the perimeter of the rectangle in question is 25 2/3 inch. I hope the procedure is clear to you.

Answer 2

Answer

The perimeter of the rectangle is $15\frac{2}{3}$

Explanation

To solve this, we are going to use the formula for the perimeter of a rectangle:

$P=2(w+l)$

where

$P$ is the perimeter of the rectangle

$w$ is the width of the rectangle

$l$ is the length of the rectangle

We can infer from our problem the the shorter strips are $2\frac{1}{2}$ inches, so $w=2\frac{1}{2}$. That leaves us with $l=5\frac{1}{3}$. Let's replace those values in our formula to find $P$:

$P=2(w+l)$

$P=2(2\frac{1}{2}+5\frac{1}{3})$

$P=2(\frac{5}{2} +\frac{16}{3} )$

$P=2(\frac{47}{6} )$

$P=\frac{47}{3}$

$P=15\frac{2}{3}$