It would be 9 because 2x9=18. Then 18+-2=16.
Answer:
Let the vectors be
a = [0, 1, 2] and
b = [1, -2, 3]
( 1 ) The cross product of a and b (a x b) is the vector that is perpendicular (orthogonal) to a and b.
Let the cross product be another vector c.
To find the cross product (c) of a and b, we have
![\left[\begin{array}{ccc}i&j&k\\0&1&2\\1&-2&3\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7Di%26j%26k%5C%5C0%261%262%5C%5C1%26-2%263%5Cend%7Barray%7D%5Cright%5D)
c = i(3 + 4) - j(0 - 2) + k(0 - 1)
c = 7i + 2j - k
c = [7, 2, -1]
( 2 ) Convert the orthogonal vector (c) to a unit vector using the formula:
c / | c |
Where | c | = √ (7)² + (2)² + (-1)² = 3√6
Therefore, the unit vector is
![\frac{[7,2,-1]}{3\sqrt{6} }](https://tex.z-dn.net/?f=%5Cfrac%7B%5B7%2C2%2C-1%5D%7D%7B3%5Csqrt%7B6%7D%20%7D)
or
[ 
, 
, 
]
The other unit vector which is also orthogonal to a and b is calculated by multiplying the first unit vector by -1. The result is as follows:
[ 
, 
, 
]
In conclusion, the two unit vectors are;
[ , , ]
and
[ , , ]
<em>Hope this helps!</em>
I answered this but i couldn’t take multiple pictures. however i found a website with the same answer as me after i answered your question. here : https://www.quora.com/How-do-I-integrate-Integrate-sinxdx-sin-3x+cos-3x
Answer: 33 days.
Step-by-step explanation:
Given :- Camryn practices the trumpet every 11th day and the flute every 3rd day.
Camryn practiced both the trumpet and the flute today.
To find the number of days until Camryn practices the trumpet and flute again in the same day, we need to find the least common multiple (L.C.M.) of 11 and 3.
As they both are co-prime numbers thus its L.C.M.= 11×3=33
Therefore, Camryn practices the trumpet and flute again in the same day after 33 days.
Answer:
<h3>x^3</h3>
Step-by-step explanation:
We are to find the greatest common factor of x^7, x^3 and x^5
x^7 = x^3 * x^4
x^3 = x^3 * 1
x^5 = x^3 * x^2
From both factors, we cam see that x^3 is common to the three, hence the GCF is x^3
