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2 years ago

10

The height of a street light is 25 feet. It casts a 20−foot shadow. At the same time, a man standing next to the street light ca

sts a 5−foot shadow. How tall is the man? If needed, round the answer to the nearest hundredth.

1 answer:

Sergio039 [100]2 years ago

8 0

The man would be 6 fooot

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2 years ago

Solve for p<br>6 = 3 + 3p<br>P=

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3 years ago

Read 2 more answers

Pumps A, B, and C operate at their respective constant rates. Pumps A and B, operating simultaneously, can fill a certain tank i

jeka94

Let $a,b,c$ be the time it takes for pumps A, B, and C (respectively) to fill 1 tank. Then

$\begin{cases}\dfrac1a+\dfrac1b=\dfrac1{\frac65}=\dfrac56\\\\\dfrac1a+\dfrac1c=\dfrac1{\frac32}=\dfrac23\\\\\dfrac1b+\dfrac1c=\dfrac12\end{cases}$

Now,

$\left(\dfrac1a+\dfrac1b\right)-\left(\dfrac1a+\dfrac1c\right)=\dfrac56-\dfrac23\implies\dfrac1b-\dfrac1c=\dfrac16$

Then

$\left(\dfrac1b+\dfrac1c\right)+\left(\dfrac1b-\dfrac1c\right)=\dfrac12+\dfrac16\implies\dfrac2b=\dfrac23\implies b=3$

This means

$\dfrac1a+\dfrac13=\dfrac56\implies\dfrac1a=\dfrac12\implies a=2$

and

$\dfrac13+\dfrac1c=\dfrac12\implies\dfrac1c=\dfrac16\implies c=6$

Working together, all 3 pumps would operate at a rate of

$\dfrac1a+\dfrac1b+\dfrac1c=1$

or 1 tank in 1 hour, so the answer is D.

8 0

2 years ago