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3 years ago

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The height of a street light is 25 feet. It casts a 20−foot shadow. At the same time, a man standing next to the street light ca

sts a 5−foot shadow. How tall is the man? If needed, round the answer to the nearest hundredth.

1 answer:

Sergio039 [100]3 years ago

8 0

The man would be 6 fooot

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Answer: y=-2x-9

Step-by-step explanation:

If ANGL is a square, then NG and LG are adjacent sides.

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What is the solution set of y< 1-6x

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Y<1-6x

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3 years ago

On a coordinate plane, a curved line with a minimum value of (5.1, negative 7) and a maximum value of (0, 25), crosses the x-axi

liubo4ka [24]

Answer:

<u>The true statement is D</u>

Step-by-step explanation:

The rest of the question is the attached figure and the statement options.

A. Over the interval [–4, –2], the local minimum is 0.
B. Over the interval [–2, –1], the local minimum is 25.
C. Over the interval [–1, 4], the local minimum is 0.
D. Over the interval [4, 7], the local minimum is -7.

============================================================

According to the graph, we will check the options:

A. Over the interval [–4, –2], the local minimum is 0. (<u>Wrong</u>)

Because the minimum is -12

B. Over the interval [–2, –1], the local minimum is 25. (<u>Wrong</u>)

Because the minimum is 18

C. Over the interval [–1, 4], the local minimum is 0. (<u>Wrong</u>)

Because the minimum is at x = 4 less than zero

D. Over the interval [4, 7], the local minimum is -7. (<u>True</u>)

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3 years ago

Read 2 more answers

Please help!! i’ll mark you as brainliest!!

PtichkaEL [24]

Answer:

For Triangle 1

a. Hypothenus = 4

b. Adjacent = 2√3

For Triangle 2:

a. Hypothenus = 2√2

b. Adjacent = 2

Step-by-step explanation:

For Triangle 1

NOTE: We shall be using angle 30°.

a. Determination of the Hypothenus.

Opposite = 2

Angle (θ) = 30°

Hypothenus =?

Sine θ = Opposite /Hypothenus

Sine 30 = 2 / Hypo

0.5 = 2 / Hypo

Cross multiply

0.5 × Hypo = 2

Divide both side by 0.5

Hypo = 2 / 0.5

Hypothenus = 4

b. Determination of the Adjacent

NOTE: We shall be using angle 30°.

Opposite = 2

Angle (θ) = 30°

Adjacent =?

Tan θ = Opposite / Adjacent

Tan 30 = 2 / Adj

1 / √3 = 2 / Adj

Cross multiply

1 × Adj = 2 × √3

Adjacent = 2√3

For Triangle 2:

a. Determination of the Hypothenus.

Opposite = 2

Angle (θ) = 45°

Hypothenus =?

Sine θ = Opposite /Hypothenus

Sine 45 = 2 / Hypo

1 / √2 = 2 / Hypo

Cross multiply

1 × Hypo = 2 × √2

Hypothenus = 2√2

b. Determination of the Adjacent

Opposite = 2

Angle (θ) = 45°

Adjacent =?

Tan θ = Opposite / Adjacent

Tan 45 = 2 / Adj

1 = 2 / Adj

Cross multiply

1 × Adj = 2

Adjacent = 2

5 0

3 years ago