Can you type it out with actual numbers instead of letters please? Thank you
Answer:
<h2>c. 2</h2>
Step-by-step explanation:
![4^\frac{1}{3}\cdot4^\frac{1}{6}\\\\\text{use}\ a^n\cdot a^m=a^{n+m}\\\\=4^{\frac{1}{3}+\frac{1}{6}}=4^{\frac{1\cdot2}{3\cdot2}+\frac{1}{6}}=4^{\frac{2}{6}+\frac{1}{6}}=4^\frac{2+1}{6}=4^\frac{3}{6}=4^\frac{3:3}{6:3}=4^{\frac{1}{2}}\\\\\text{use}\ a^\frac{m}{n}=\sqrt[n]{a^m}\\\\=\sqrt[2]{4^1}=\sqrt4=2](https://tex.z-dn.net/?f=4%5E%5Cfrac%7B1%7D%7B3%7D%5Ccdot4%5E%5Cfrac%7B1%7D%7B6%7D%5C%5C%5C%5C%5Ctext%7Buse%7D%5C%20a%5En%5Ccdot%20a%5Em%3Da%5E%7Bn%2Bm%7D%5C%5C%5C%5C%3D4%5E%7B%5Cfrac%7B1%7D%7B3%7D%2B%5Cfrac%7B1%7D%7B6%7D%7D%3D4%5E%7B%5Cfrac%7B1%5Ccdot2%7D%7B3%5Ccdot2%7D%2B%5Cfrac%7B1%7D%7B6%7D%7D%3D4%5E%7B%5Cfrac%7B2%7D%7B6%7D%2B%5Cfrac%7B1%7D%7B6%7D%7D%3D4%5E%5Cfrac%7B2%2B1%7D%7B6%7D%3D4%5E%5Cfrac%7B3%7D%7B6%7D%3D4%5E%5Cfrac%7B3%3A3%7D%7B6%3A3%7D%3D4%5E%7B%5Cfrac%7B1%7D%7B2%7D%7D%5C%5C%5C%5C%5Ctext%7Buse%7D%5C%20a%5E%5Cfrac%7Bm%7D%7Bn%7D%3D%5Csqrt%5Bn%5D%7Ba%5Em%7D%5C%5C%5C%5C%3D%5Csqrt%5B2%5D%7B4%5E1%7D%3D%5Csqrt4%3D2)
12 ^3 and 11^3 haven't got the same base so the rules of exponents do not apply.
Bases have to be the same:- for example 12^3 * 12*3 = 12 ^(3+3) = 12^6
It's pretty much simple. Since we can factor a polynomial by its zeros, lets write one of degree nine :
X(X-1)(X-2)(X-3)(X-4)(X-5)(X+1)(X+2)(X+3)= X^9-9X^8+6X^7+126X^6-231X^5-441X^4+944X^3+324X^2-720X
This polynomial is of degree 9 and has exactly 5 strictly positive zeros : 1, 2, 3, 4, 5
And it has 3 negative zeros : - 1, -1, - 3
And it has 0 as a zero too.
There is also this one :
(X-1)(X-2)(X-3)(X-4)(X²+1)(X+1)(X+2)(X+3) = X^9-4X^8-13X^7+52X^6+35X^5-140X^4+13X^3-52X^2-36X+144
It has 4 positive zeros : 1, 2, 3, 4.
It has complex zeros : i and - i
3 negative zeros : - 1, - 2 , - 3
Good Luck
Answer:
The answer is given below
Step-by-step explanation:
a)
Let us assume Patricia baked x number of cakes. She put half of the cupcakes (i.e x/2) equally into 6 big boxes.
6 big boxes contained 
cakes, therefore 1 big box would contain 
cakes.
Let us assume she put the other half into 14 small boxes, therefore each small box would contain 
cakes.
There were 45 cupcakes in 3 big boxes and 8 small boxes altogether. That is:
Therefore Patricia baked 84 cup cakes
b)
She sold all the small boxes and collected $189, i.e she sold 14 small box for $189. Each small box = $189/14 = $13.5
