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kiruha [24]
3 years ago
14

Solve for x. m<8 = + 52​

Mathematics
1 answer:
pochemuha3 years ago
8 0

Answer:

8/52=m/39 cross multiply.

52m=8*39

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If h(x) is the inverse of f(x), what is the value of h(f(x))?<br> оо<br> 0 1<br> ООО<br> o f(x)
mart [117]

Answer:

x.

Step-by-step explanation:

If h(x) is the inverse of f(x) them h(f(x)) = x.

7 0
4 years ago
A recent study reported that diastolic blood pressures of adult women in the United States are approximately normally distribute
Zina [86]

Answer:

Proportion of women having blood pressures between 88.1 and 89.4 is 3.99% or close to 4%.

Step-by-step explanation:

We are given that a recent study reported that diastolic blood pressures of adult women in the United States are approximately normally distributed with mean 80.3 and standard deviation 8.6.

Let X = blood pressures of adult women in the United States

So, X ~ N(\mu=80.3,\sigma^{2} =8.6^{2})

The z score probability distribution is given by;

              Z = \frac{X-\mu}{\sigma} ~ N(0,1)  

where, \mu = population mean

           \sigma = population standard deviation

So, Probability that women have blood pressures between 88.1 and 89.4 is given by = P(88.1 < X < 89.4) = P(X < 89.4) - P(X \leq 88.1)

   P(X < 89.4) = P( \frac{X-\mu}{\sigma} < \frac{89.4-80.3}{8.6} ) = P(Z < 1.05) = 0.85314

   P(X \leq 88.1) = P( \frac{X-\mu}{\sigma} \leq \frac{88.1-80.3}{8.6} ) = P(Z \leq 0.89) = 0.81327

Therefore, P(88.1 < X < 89.4) = 0.85314 - 0.81327 = 0.0399 or approx 4%

Hence, proportion of women have blood pressures between 88.1 and 89.4 is 4%.

7 0
4 years ago
You represent a chemical company that is being sued for paint damage to automobiles. You want to support the claim that the mean
denpristay [2]

Correct question is;

You represent a chemical company that is being sued for paint damage to automobiles. You want to support the claim that the mean repair cost per automobile is more than $650. How would you write the null and alternative hypotheses?

A) State the null and alternative hypotheses in words (context of the problem)

B) Write the null and alternative hypotheses in appropriate symbols (population parameters μ, σ or p)

C) Describe in words Type I error (the consequence of rejecting a true null hypothesis.)

D) Describe in words Type II error (the consequence of failing to reject a false null hypothesis.)

Answer:

A)In words;

Null hypothesis is that the cost is $650

Alternative hypothesis is that the cost is not $650

B) Null hypothesis; μ = 650

Alternative hypothesis; μ ≠ 650

C) Type I Error will be to make a claim that the repair cost is not $650, when it is actually $650.

D) Type II Error will be to make a claim that the repair cost is not $650, but fail to reject the claim that it is $650.

Step-by-step explanation:

We are told that You want to support the claim that the mean repair cost per automobile is more than $650.

Thus;

A)In words;

Null hypothesis is that the cost is $650

Alternative hypothesis is that the cost is not $650

B) Null hypothesis; μ = 650

Alternative hypothesis; μ ≠ 650

C) Type I Error will be to make a claim that the repair cost is not $650, when it is actually $650.

D) Type II Error will be to make a claim that the repair cost is not $650, but fail to reject the claim that it is $650.

6 0
3 years ago
Need help solving these questions need answers fast
const2013 [10]

Answer:

First image: Q

Second image: I think B

Step-by-step explanation:

8 0
4 years ago
Read 2 more answers
10.3)200.3865<br> 10.3 divided by 200.3865
Varvara68 [4.7K]

Answer:

1

Step-by-step explanation:

200.3865 divided by 200.3865 equals 1

7 0
3 years ago
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