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Bas_tet [7]
3 years ago
10

9 less than the product of 5 and a number n

Mathematics
2 answers:
Lady_Fox [76]3 years ago
7 0

Answer:

9-5n

Step-by-step explanation:

9-5(N)=9-5n

d1i1m1o1n [39]3 years ago
6 0

Answer:

(5n) - 9

Step-by-step explanation:

Product of 5 and a number n: 5 x n ; 5(n)

9 less than: - 9

5n - 9 is your answer

~

You might be interested in
Whats the awenser for (9m - 6)7
svet-max [94.6K]
(9m - 6)7
Distribute 7 to both sides
63m - 42
Add 42 to get 63m by itself
63m = 42
Divide both sides by 63
m = 42/63 or simplified, 2/3
7 0
3 years ago
3
dem82 [27]

Answer:

y = 2x - 19

Step-by-step explanation:

Slope-intercept form: y = mx + b

y = (x , y) = 1

m = slope = 2

x = (x , y) = 10

b = y-intercept

Plug in the corresponding numbers to the corresponding variables:

1 = 2(10) + b

First, simplify, and then isolate the variable, b. Note the equal sign, what you do to one side, you do to the other.

First, multiply 2 with 10:

1 = (2 * 10) + b

1 = 20 + b

Next, subtract 20 from both sides of the equation:

1 = b + 20

1 (-20) = b + 20 (-20)

1 - 20 = b

b = -19

Plug in 2 for m, and -19 for b.

y = 2x - 19 is your slope-intercept form.

~

8 0
3 years ago
Nnnnnnnnnnnnnnnnnnnnnnnnnnnneeeeeeeeeeeeeeeeeeeeed
alina1380 [7]

Answer:

x = 75

Step-by-step explanation:

x/5 = 15 divide both sides by 5 to get rid of fraction

5 × x/5 = 15 × 5

x = 75

8 0
3 years ago
Write an equation for a circle with a radius of 5 and a center located at point (2,8)
Dmitrij [34]
A circles equation is
(x – h)^2 + (y – k)^2 = r^2
The center is at the point (h, k)
The radius is r.

Your circles equation is:
(x – 2)^2 + (y – 8)^2 = 5^2
5 0
3 years ago
Evaluate Combination (6,6)
andrew11 [14]

Answer:

nCx = \frac{n!}{x! (n-x)!}

On this case n =6 and x =6 we got:

6C6 = \frac{6!}{6! (6-6)!} = \frac{6!}{6! 0!}= \frac{6!}{6!}=1

Step-by-step explanation:

The utility for the combination formula is in order to find the number of ways to order a set of elements

For this case we want to find the following expression:

6C6

And the general formula for combination is given by:

nCx = \frac{n!}{x! (n-x)!}

On this case n =6 and x =6 we got:

6C6 = \frac{6!}{6! (6-6)!} = \frac{6!}{6! 0!}= \frac{6!}{6!}=1

8 0
3 years ago
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