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2 years ago

Tom gets $12 off a box of chocolates that had an original price of $48.What percentage is the discount

Mathematics

2 answers:

Nana76 [90]2 years ago

7 0

Answer:

25 percent

Step-by-step explanation:multiply 48 by .25 it will give you 12 which is the discount hope this helps god bless

Pie2 years ago

3 0

Answer:

25%

Step-by-step explanation:

12/48=.25=25%

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Please help with these 2 answers i only have 10 minutes left

natta225 [31]

Answer:

1/4 of a pound
4/15 of the flat

Step-by-step explanation:

For number 1:

3/4 ÷ 3 = 0.25
0.25 = 1/4

For number 2:

4/5 ÷ 3 = 4/15

I hope this helps!

5 0

2 years ago

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Is 5/3 a irrational number

Nataly [62]

Answer: No

Step-by-step explanation: To determine whether 5/3 is rational or irrational, it's important to understand that all fractions positive or negative are rational numbers.

So 5/3 is not an irrational number, it's rational.

4 0

3 years ago

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A scale drawing of a pool has scale of 1 in :4 ft. If the actual pool is 16 ft wide, how is the pool represented in the drawing

Deffense [45]

Answer: 4 inches

Step-by-step explanation:

Let the width of the pool in the drawing be represented by x.

Since scale drawing of a pool has scale of 1 in :4 ft and the actual pool is 16 ft wide, this can be represented in an equation as:

1/4 = x/16

Cross multiply

4 × x = 1 × 16

4x = 16

x = 16/4

x = 4

Therefore, the pool representation in the drawing is 4 inches

8 0

2 years ago

The points A(1, 4), B(5,1) lie on a circle. The line segment AB is a chord. Find the equation of a diameter of the circle.

tangare [24]

Check the picture below.

well, we want only the equation of the diametrical line, now, the diameter can touch the chord at any several angles, as well at a right-angle.

bearing in mind that <u>perpendicular lines have negative reciprocal</u> slopes, hmm let's find firstly the slope of AB, and the negative reciprocal of that will be the slope of the diameter, that is passing through the midpoint of AB.

$\bf A(\stackrel{x_1}{1}~,~\stackrel{y_1}{4})\qquad B(\stackrel{x_2}{5}~,~\stackrel{y_2}{1}) ~\hfill \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{1}-\stackrel{y1}{4}}}{\underset{run} {\underset{x_2}{5}-\underset{x_1}{1}}}\implies \cfrac{-3}{4} \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\textit{slope of AB}}{-\cfrac{3}{4}}\qquad \qquad \qquad \stackrel{\textit{\underline{negative reciprocal} and slope of the diameter}}{\cfrac{4}{3}}$

so, it passes through the midpoint of AB,

$\bf ~~~~~~~~~~~~\textit{middle point of 2 points } \\\\ A(\stackrel{x_1}{1}~,~\stackrel{y_1}{4})\qquad B(\stackrel{x_2}{5}~,~\stackrel{y_2}{1}) \qquad \left(\cfrac{ x_2 + x_1}{2}~~~ ,~~~ \cfrac{ y_2 + y_1}{2} \right) \\\\\\ \left( \cfrac{5+1}{2}~~,~~\cfrac{1+4}{2} \right)\implies \left(3~~,~~\cfrac{5}{2} \right)$

so, we're really looking for the equation of a line whose slope is 4/3 and runs through (3 , 5/2)

$\bf (\stackrel{x_1}{3}~,~\stackrel{y_1}{\frac{5}{2}}) \stackrel{slope}{m}\implies \cfrac{4}{3} \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{\cfrac{5}{2}}=\stackrel{m}{\cfrac{4}{3}}(x-\stackrel{x_1}{3})\implies y-\cfrac{5}{2}=\cfrac{4}{3}x-4 \\\\\\ y=\cfrac{4}{3}x-4+\cfrac{5}{2}\implies y=\cfrac{4}{3}x-\cfrac{3}{2}$