Answer:
If the null hypothesis is true in a chi-square test, discrepancies between observed and expected frequencies will tend to be small enough to qualify as a common outcome.
Step-by-step explanation:
Here in this question, we want to state what will happen if the null hypothesis is true in a chi-square test.
If the null hypothesis is true in a chi-square test, discrepancies between observed and expected frequencies will tend to be small enough to qualify as a common outcome.
This is because at a higher level of discrepancies, there will be a strong evidence against the null. This means that it will be rare to find discrepancies if null was true.
In the question however, since the null is true, the discrepancies we will be expecting will thus be small and common.
19/25 is the answer
hope i helped!
Answer:
The correct option is C
Step-by-step explanation:
A: We know that the lower quartile is 144, and the upper quartile is 129.5 is you add them all up it is going to equal 273.3. So we know that A can now be crossed out.
B: We know that the lower quartile is 146, and that means the upper quartile is 136.5. So adding all of these numbers up we ill get 282.5 So now <u>B can be crossed out</u>
C: The lower quartile is 114 and the upper quartile is 129.5 and when we add those two numbers up we are going to get 243.5. So we are going to keep this number
D: For the last one we know the lower quartile is 214 and upper is 129.5, and when we add this we get 343.5. So we can cross this out and<u> the only one we have left is going to be C</u>
<u>Hope this help's</u>
Answer:
0.43
Step-by-step explanation:
2+3+1+1=7
7*4+28==Area of full shape
(2*4)+(1*4)=12==Area of shaded shapes
12/28=0.428571>rounded up>0.43
The population of a town has approximately doubled every 17 years since 1950.
the equation P=
where Po is the population of the town in 1950, is used to model the population, P, of the town t years after 1950.
When t=17 yrs
P=2
for 1 year
The equation becomes
P = 
-------------(1)
Our original equation is
----------------------------------(2)
equating expression 1 and 2
Cancelling 
from both sides we get
t/17=k
⇒k=t/17 is the solution.
