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PilotLPTM [1.2K]
3 years ago
12

A plane is defined as what type of figure? A. 1-dimensional B. 2-dimensional C. 3-dimensional D. A plane has no dimensions.

Mathematics
1 answer:
Dmitry_Shevchenko [17]3 years ago
6 0

A plane is defined as a figure that has B, two dimensions.

This question is about definitions, and the definition of a plane is that it is a flat surface with two dimensions. But, since everything in our world is 3 dimensions (everything, even if it looks small, has some kind of depth), there are no planes in our world. A plane also extends infinitely far, and can be named by 3 points on it.

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Amber saved a total of $3.20 over 5 weeks. She saved the same amount of money each week.
dybincka [34]

Answer:

0.64

Step-by-step explanation:

you just divide 3.20 by 5

3 0
3 years ago
Read 2 more answers
What is the measure of 0 in radians?
Allushta [10]

Answer:

Thus, the expression to find the measure of θ in radians is θ = π÷3

Step-by-step explanation:

Given that the radius of the circle is 3 units.

The arc length is π.

The central angle is θ.

We need to determine the expression to find the measure of θ in radians.

Expression to find the measure of θ in radians:

The expression can be determined using the formula,

where S is the arc length, r is the radius and θ is the central angle in radians.

Substituting S = π and r = 3, we get;

Dividing both sides of the equation by 3, we get;

3 0
3 years ago
In the diagram, AABC ~ ADEF. Find the value of x.
Andrew [12]

Answer:

B

Step-by-step explanation:

bdeehvdvjwjkwkwwjehheeh

If you dont know the anwser its always B

3 0
2 years ago
Outside temperature over a day can be modeled as a sinusoidal function. Suppose you know the temperature varies between 73 and 9
Naddika [18.5K]

Answer: After about 9.03 hours the temperature first reach 82 degrees.

Step-by-step explanation:

The sinusoidal function is given by :

y=A\sin[\omega(x-\alpha)]+C

where, A =  amplitude; \omega=\dfrac{2\pi}{period} ,  α= phase shift on the Y-axis and C = midline.

As per given,

Average daily temperature= C=\dfrac{73+97}{2}=85   [midline is average of upper and lower limit.]

A=  97-85 = 12

Phase shift: \alpha=10

Period = 24 hours;

\omega=\dfrac{2\pi}{24}=\dfrac{\pi}{12}

Substitute all values in sinusoidal function, we get

y=12\sin[\dfrac{\pi}{12}(x-10)]+85

Put y= 82, we get

82=12\sin[\dfrac{\pi}{12}(x-10)]+85\\\\\Rightarrow\ -3= 12\sin[\dfrac{\pi}{12}(x-10)]\\\\=\dfrac{-1}{4}= \sin[\dfrac{\pi}{12}(x-10)]\\\\\Rightarrow\ \dfrac{\pi}{12}(x-10)=\sin^{-1}(\dfrac{-1}{4})\\\\\Rightarrow\ x-10=\dfrac{12}{\pi}(\sin^{-1}(\dfrac{-1}{4}))\\\\\Rightarrow\ x=\dfrac{12}{\pi}(\sin^{-1}(\dfrac{-1}{4}))+10\\\Rightarrow\ x\approx9.03

Hence, After about 9.03 hours the temperature first reach 82 degrees.

3 0
2 years ago
Divide -3x^3-2x^2-x-2 by x-2
Rasek [7]

Let's do this by Briot-Ruffini


First: Find the monomial root


x - 2 = 0

x = 2


Second: Allign this root with all the other coeficients from equation

Equation = -3x³ - 2x² - x - 2

Coeficients = -3, -2, -1, -2

2 | -3 -2 -1 -2


Copy the first coeficient


2 | -3 -2 -1 -2

-3


Multiply him by the root and sum with the next coeficient


2.(-3) = -6

-6 + (-2) = -8


2 | -3 -2 -1 -2

-3 -8


Do the same


2.(-8) = -16

-16 + (-1) = -17


2 | -3 -2 -1 -2

-3 -8 -17


The same,


2.(-17) = -34

-34 + (-2) = -36


2 | -3 -2 -1 -2

-3 -8 -17 -36


Now you just need to put the "x" after all these numbers with one exponent less, see


2 | -3x³ - 2x² - 1x - 2

-3x² - 8x - 17 -36


You may be asking what exponent -36 should be, and I say:


None or the monomial. He's like the rest of this division, so you can say:


(-3x³ - 2x² - x - 2)/(x - 2) = -3x² - 8x - 17 with rest -36 or you can say:

(-3x³ - 2x² - x - 2)/(x - 2) = -3x² - 8x - 17 - 36/(x - 2)


Just divide the rest by the monomial.

5 0
3 years ago
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