Answer:

Step-by-step explanation:
The equation of a parabola in vertex form:

<em>(h, k)</em><em> - vertex</em>
The focus is

We have the vertex (2, -5) and the focus (2, -4).
Calculate the value of <em>a</em> using 
<em>k = -5</em>
<em>add 5 to both sides</em>
<em>multiply both sides by 4</em>


Substitute

to the vertex form of an equation of a parabola:

The standard form:

Convert using


<em>use the distributive property: a(b+c)=ab+ac</em>

If you meant 2x + 2x + 1 = 17: x = 4
Solve for x by simplifying both sides of the equation, then isolating the variable.<span>
</span>
If you meant <span>x2 + 2x + 1 = 17:</span> <span>x ≈ 3.1231056,−5.1231056x</span>
Solve the equation for x by finding a, b, and c of the quadratic then applying the quadratic formula. <span><span>x = −1 ± <span>√17</span></span>x</span>
Answer:
Check the explanation
Step-by-step explanation:
Let X denotes steel ball and Y denotes diamond
= 1/9( 50+57+......+51+53)
=530/9
=58.89
= 1/9( 52+ 56+....+ 51+ 56)
=543/9
=60.33
difference = d =(60.33- 58.89)
=1.44

s12 = 1/9( 502+572+......+512+532) -9/8 (58.89)2
=31686/8 - 9/8( 3468.03)
=3960.75 - 3901.53
=59.22
s1 = 7.69
s22 = 1/9( 522+ 562+....+ 512+ 562) -9/8 (60.33)2
=33295/8 - 9/8 (3640.11)
=4161.875 - 4095.12
=66.75
s2 =8.17
sample standard deviation for difference is
s=![\sqrt{[(n1-1)s_1^2+ (n2-1)s_2^2]/(n1+n2-2)}](https://tex.z-dn.net/?f=%5Csqrt%7B%5B%28n1-1%29s_1%5E2%2B%20%28n2-1%29s_2%5E2%5D%2F%28n1%2Bn2-2%29%7D)
= ![\sqrt{[(9-1)*59.22+ (9-1)*66.75]/(9+9-2)}](https://tex.z-dn.net/?f=%5Csqrt%7B%5B%289-1%29%2A59.22%2B%20%289-1%29%2A66.75%5D%2F%289%2B9-2%29%7D)
= 
=7.93
sd = 
=
=7.93* 0.47
=3.74
For 95% confidence level
=1.96
confidence interval is

=(1.44 - 1.96* 3.75 , 1.44+1.96* 3.75)
=(1.44 - 7.35 , 1.44 + 7.35)
=(-2.31, 8.79)
There is sufficient evidence to conclude that the two indenters produce different hardness readings.
The initial velocity: v o = 20 m/s.And : a = 1.5 m / s² , t = 5 s.The final velocity formula:v = v o + a · tv = 20 + 1.5 · 5v = 20 + 7.5v = 27.5 m /sAnswer: The car`s final velocity is 27.5 meters / second.
Answer is A
Hope it helps