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3 years ago

PLEASE HELP ASAP i will give brainliest!!

Mathematics

2 answers:

kow [346]3 years ago

7 0

Answer:

1. the cost of the computer (c)

2. > (greater than)

3. how much ($300)

4. c > 300

USPshnik [31]3 years ago

4 0

Answer:

1. the cost of the computer

2. >

3. 300

4. c > 300

Step-by-step explanation:

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Footballs sell for $27.99 each at Dicks Sporting Goods and $21.59 each at Big 5. If the coach buys a dozen footballs, how much c

klasskru [66]

Answer:

The money he can save by buying them at Big 5 is $76.80.

Step-by-step explanation:

Given:

Footballs sell for $27.99 each at Sporting Goods.

Footballs sell for $21.59 each at Big 5.

The coach buys a dozen footballs.

Now, to find the amount he save by buying them at Big 5.

So, first we find the cost of footballs at Sporting Goods and at Big 5.

1 Dozen = 12 pieces.

Thus, the cost of footballs at Sporting Goods =

$\$27.99\times 12 =\$335.88$

And, the cost of footballs at Big 5 =

$\$21.59\times 12=\$259.08.$

Now, to get the amount coach can save by buying them at Big 5, we subtract both the cost as the cost of Sporting Goods is more than the Cost of Big 5:

The amount coach can save by buying them at Big 5 =

$\$335.88-\$259.08=\$76.80.$

Therefore, the amount he can save by buying them at Big 5 is $76.80.

7 0

3 years ago

17. According to the Associative Property, which expression is equal to (12)(7)(6x)?

Dvinal [7]

(12)(7)(6x)=504x

(12 * 7 * 6)(x)=504x

(7)(12)(6) + x=504+x

12(7 + 6x)=84+72x

12 + 7 + 6x=19+x

wee see that

A*B=(A)(B)

5 0

3 years ago

Read 2 more answers

2. ANSWER=

mixas84 [53]

Answer:

a yes udjwjwjwjwjwjwjwjwjw

yes men es chef

6 0

2 years ago

Find the absolute maximum and minimum values of the following function on the specified region R.

yan [13]

Answer:

Step-by-step explanation:

Since it is said that the region R is a semicircular disc, we asume that the boundaries of the region are given by $-2\leq x \leq 2, 0\leq y \leq \sqrt[]{4-x^2}$ . First, we must solve the optimization problem without any restrictions, and see if the points we get lay inside the region of interest. To do so, consider the given function F(x,y). We want to find the point for which it's gradient is equal to zero, that is

$\frac{dF}{dx}=9y=0$

$\frac{dF}{dy}=9x=0$

This implies that (x,y) = (0,0). This point lays inside the region R. We will use the Hessian criteria to check if its a minimum o r a maximum. To do so, we calculate the matrix of second derivates

$\frac{d^2F}{dx^2} = 0 = \frac{d^2F}{dy^2}$

$\frac{d^2F}{dxdy} = 9 = \frac{d^2F}{dydx}$

so we get the matrix

$\left[\begin{matrix} 0 & 9 \\ 9 & 0\end{matrix}\right]$

Note that the first determinant is 0, and the second determinant is -9. THis tell us that the point is a saddle point, hence not a minimum nor maximum.

Since the function is continous and the region R is closed and bound (hence compact) the maximum and minimum must be attained on the boundaries of R. REcall that when $-2\leq x \leq x$ and y=0 we have that F(x,0) = 0. So, we want to pay attention to the critical values over the circle, restricting that the values of y must be positive. To do so, consider the following function

$H(x,y, \lambda) = 9xy - \lambda(x^2+y^2-4)$ which consists of the original function and a function that describes the restriction (the circle x^2+y^2=4), we want that the gradient of H is 0.

Then,

$\frac{dH}{dx} = 9y-2\lambda x =0$

$\frac{dH}{dx} = 9x-2\lambda y =0$

$\frac{dH}{d\lambda} = x^2+y^2-4 =0$

From the first and second equation we get that

$\lambda = \frac{9y}{2x} = \frac{9x}{2y}$

which implies that $y^2=x^2$ . If we replace this in the restriction, we have that $x^2+x^2 = 2x^2 = 4$ which gives us that $x=\pm \sqrt[]{2}$ . Since we only care for the positive values of y, and that $y=\pm x$ , we have the following critical points $(\sqrt[]{2},\sqrt[]{2}), (-(\sqrt[]{2},\sqrt[]{2})$ . Note that for the first point, the value of the function is