Answer: −1/8
Step-by-step explanation: maybe
Ik for s fact the awnser not a
Answer:
12 meters
Step-by-step explanation:
Looking at the problem we can see that it typifies a right angled triangle. The rope running from the top of the flagpole to the hook on the ground is the hypotenuse of the triangle. Let us call this hypotenuse c. Let the distance between the hook and the foot of the flagpole be b. Let the height of the flagpole be a.
From Pythagoras theorem;
c^2 = a^2 + b^2
a^2= c^2 - b^2
a= √c^2-b^2
From the question
c= 13 metres
b= 5 metres
a= the unknown
a= √c^2-b^2
a= √(13)^2 - (5)^2
a= √169 - 25
a= √144
a= 12 meters
Answer:
AY=8, XZ=20
Step-by-step explanation:
WY=WA+AY, plug in values: 14=6+AY, subtract 6 from both sides: 8=AY, AY=8cm
ZA=10cm and WY bisects XZ at A, so XA=ZA and XZ = XA+ZA = 2ZA =2*10 = 20 cm
