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zubka84 [21]
3 years ago
11

What is an expression that is four times as large as 52 minus 9.

Mathematics
2 answers:
Rina8888 [55]3 years ago
5 0

Answer:

4(52-9)

4(43)

172

Please mark as brainliest! Good Luck! :D

SashulF [63]3 years ago
3 0

Answer:

4(52-9)

4(43)

172

Step-by-step explanation:

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Kevin buys
algol [13]

Answer:

1:350 i think

Step-by-step explanation:

i could be wrong

7 0
2 years ago
Read 2 more answers
1/2x - 7 = 1/3 (x-12)
Volgvan
So this is the answer:)))))

7 0
3 years ago
Pineview Middle School has 158 fewer students enrolled than Wellington Middle School. If Pineview Middle has 1039 students enrol
vampirchik [111]
1039 + 158 = 1197 students
8 0
2 years ago
The Slow Ball Challenge or The Fast Ball Challenge.
cupoosta [38]

Answer:

Fast ball challenge

Step-by-step explanation:

Given

Slow Ball Challenge

Pitches = 7

P(Hit) = 80\%

Win = \$60

Lost = \$10

Fast Ball Challenge

Pitches = 3

P(Hit) = 70\%

Win = \$60

Lost = \$10

Required

Which should he choose?

To do this, we simply calculate the expected earnings of both.

Considering the slow ball challenge

First, we calculate the binomial probability that he hits all 7 pitches

P(x) =^nC_x * p^x * (1 - p)^{n - x}

Where

n = 7 --- pitches

x = 7 --- all hits

p = 80\% = 0.80 --- probability of hit

So, we have:

P(x) =^nC_x * p^x * (1 - p)^{n - x}

P(7) =^7C_7 * 0.80^7 * (1 - 0.80)^{7 - 7}

P(7) =1 * 0.80^7 * (1 - 0.80)^0

P(7) =1 * 0.80^7 * 0.20^0

Using a calculator:

P(7) =0.2097152 --- This is the probability that he wins

i.e.

P(Win) =0.2097152

The probability that he lose is:

P(Lose) = 1 - P(Win) ---- Complement rule

P(Lose) = 1 -0.2097152

P(Lose) = 0.7902848

The expected value is then calculated as:

Expected = P(Win) * Win + P(Lose) * Lose

Expected = 0.2097152 * \$60 + 0.7902848 * \$10

Using a calculator, we have:

Expected = \$20.48576

Considering the fast ball challenge

First, we calculate the binomial probability that he hits all 3 pitches

P(x) =^nC_x * p^x * (1 - p)^{n - x}

Where

n = 3 --- pitches

x = 3 --- all hits

p = 70\% = 0.70 --- probability of hit

So, we have:

P(3) =^3C_3 * 0.70^3 * (1 - 0.70)^{3 - 3}

P(3) =1 * 0.70^3 * (1 - 0.70)^0

P(3) =1 * 0.70^3 * 0.30^0

Using a calculator:

P(3) =0.343 --- This is the probability that he wins

i.e.

P(Win) =0.343

The probability that he lose is:

P(Lose) = 1 - P(Win) ---- Complement rule

P(Lose) = 1 - 0.343

P(Lose) = 0.657

The expected value is then calculated as:

Expected = P(Win) * Win + P(Lose) * Lose

Expected = 0.343 * \$60 + 0.657 * \$10

Using a calculator, we have:

Expected = \$27.15

So, we have:

Expected = \$20.48576 -- Slow ball

Expected = \$27.15 --- Fast ball

<em>The expected earnings of the fast ball challenge is greater than that of the slow ball. Hence, he should choose the fast ball challenge.</em>

5 0
3 years ago
The following back to back stemplot represents the amount a sample of students spent on their last haircut. Because there are si
krek1111 [17]

The 5 - number summary of the distribution obtained from the boxplot is :

  • Minimum = 20
  • Maximum = 85
  • Lower quartile = 35
  • Median = 44
  • Upper quartile = 58
  • Outlier = 100

Firstly, we need to extract the values for the amount spent by females :

20, 25, 25, 35, 37, 38, 39, 43, 45, 46, 50, 53, 60, 70, 85, 100

The five number summary include ;

  • Minimum, lower Quartile, Median, Upper Quartile and Maximum values.

Rearranging the data in ascending order :

20, 25, 25, 35, 37, 38, 39, 43, 45, 46, 50, 53, 60, 70, 85, 100

The boxplot clearly and easily gives the five number summary of the distribution :

  • Minimum = 20 (starting point of the whisker)
  • Lower quartile = 35 (starting point of the box)
  • Median = 44 (vertical line in between the box)
  • Upper quartile = 58 (endpoint of the box)
  • Maximum = 85 (endpoint of the upper whisker).

Outlier :

  • Lower boundary = LOWER QUARTILE - (1.5 × IQR)
  • Upper boundary = UPPER QUARTILE + (1.5 × IQR)
  • IQR = UPPER QUARTILE - LOWER QUARTILE
  • IQR = (58 - 35) = 23

Lower boundary = 35 - (1.5 × 23) = 0.5

Upper boundary = 58 + (1.5 × 23) = 92.5

  • The point denoted by a dot on the boxplot is an outlier = 100

Hence, values lesser than 0.5 or greater than 92.5 are outliers.

Therefore, 100 is an outlier.

Learn more : brainly.com/question/24582786

7 0
2 years ago
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