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zubka84 [21]
3 years ago
11

What is an expression that is four times as large as 52 minus 9.

Mathematics
2 answers:
Rina8888 [55]3 years ago
5 0

Answer:

4(52-9)

4(43)

172

Please mark as brainliest! Good Luck! :D

SashulF [63]3 years ago
3 0

Answer:

4(52-9)

4(43)

172

Step-by-step explanation:

You might be interested in
given the recursive formula for a geometric sequence find the common ratio the 8th term and the explicit formula.did I set these
lesya [120]

Answer:


Step-by-step explanation:

1)Since we know that recursive formula of the geometric sequence is

a_{n}=a_{n-1}*r

so comparing it with the given recursive formula a_{n}=a_{n-1}*-4

we get common ratio =-4

8th term= a_{1}*(r)^{n-1}=-2*(-4)^{7} =32768.

Explicit Formula =-2*(-4)^{n-1}

2) Comparing the given recursive formula a_{n}=a_{n-1}*-2

with standard recursive formula a_{n}=a_{n-1}*r

we get common ratio =-2

8th term= a_{1}*(r)^{n-1}=-4*(-2)^{7} =512.

Explicit Formula =-4*(-2)^{n-1}

3)Comparing the given recursive formula a_{n}=a_{n-1}*3

with standard recursive formula a_{n}=a_{n-1}*r

we get common ratio =3

8th term= a_{1}*(r)^{n-1}=-1*(3)^{7} =-2187.

Explicit Formula =-1*(3)^{n-1}

4)Comparing the given recursive formula a_{n}=a_{n-1}*-4

with standard recursive formula a_{n}=a_{n-1}*r

we get common ratio =-4

8th term= a_{1}*(r)^{n-1}=3*(-4)^{7} =-49152.

Explicit Formula =3*(-4)^{n-1}

5)Comparing the given recursive formula a_{n}=a_{n-1}*-4

with standard recursive formula a_{n}=a_{n-1}*r

we get common ratio =-4

8th term= a_{1}*(r)^{n-1}=-4*(-4)^{7} =65536.

Explicit Formula =-4*(-4)^{n-1}

6)Comparing the given recursive formula a_{n}=a_{n-1}*-2

with standard recursive formula a_{n}=a_{n-1}*r

we get common ratio =-2

8th term= a_{1}*(r)^{n-1}=3*(-2)^{7} =-384.

Explicit Formula =3*(-2)^{n-1}

7)Comparing the given recursive formula a_{n}=a_{n-1}*-5

with standard recursive formula a_{n}=a_{n-1}*r

we get common ratio =-5

8th term= a_{1}*(r)^{n-1}=4*(-5)^{7} =-312500.

Explicit Formula =4*(-5)^{n-1}

8)Comparing the given recursive formula a_{n}=a_{n-1}*-5

with standard recursive formula a_{n}=a_{n-1}*r

we get common ratio =-5

8th term= a_{1}*(r)^{n-1}=2*(-5)^{7} =-156250.

Explicit Formula =2*(-5)^{n-1}

6 0
3 years ago
2(b+3c) equivalent expressions<br>Options: <br><br>3(b+2c)<br>(b+3c) +(b+3c)<br>None of the above
Lana71 [14]
2(b + 3c) → We first need to simplify this.

Simplify.

2b + 6c

1st Option : 

3(b + 2c)

Simplify.

3b + 6c

This is INCORRECT, as it is not equal to 2b + 6c.

2nd Option :

(b + 3c) + (b + 3c)

Simplify.

2b + 6c

This is CORRECT because 2b+6c = 2b+6c

(b + 3c) + (b + 3c)  → Answer

~Hope I helped!~



5 0
2 years ago
A crab walk 1/12 of a mile an hour. The crab 1/5 of a mile away from the beach . How long will it take the crab to reach the bea
marysya [2.9K]

Answer:

2.4 hours

Step-by-step explanation:

\frac{1}{5} /\frac{1}{12}

2.4 hours

3 0
3 years ago
An unbiased coin is tossed 15 times. In how many ways can the coin land tails either exactly 8 times orexactly 5 times?
Kitty [74]

Answer:

Probability to get tails exactly 8 times or exactly 5 times is 0.29

Step-by-step explanation:

No of ways the coins lands tails exactly 8 times

P(8) = 15C8 × 0.5^{8} × 0.5^{15-8}

No of ways the coin lands tails exactly 5 times

P(5) = 15C5 × 0.5^{5} × 0.5^{15-5}

Probability to get tails exactly 8 times or 5 times

P(8)+P(5) =  15C8 × 0.5^{15} + 15C5 × 0.5^{15}

P = 0.5^{15} (  15C8 + 15C5 )

P = 0.5^{15} ( (  \frac{15!}{8!(15-8)!}  ) + ( \frac{15!}{5!(15-5)!} ) )

P = 0.5^{15} ( 6435 + 3003 )

P = 0.5^{15} ( 9438)

P = 0.5^{14} ( 4719)

P =  \frac{4719}{16384}

P = 0.29

8 0
3 years ago
A company manufactures handband a wirleless
PIT_PIT [208]

Answer:

1. 21 represents the cost of manufacturing one handband.

3. The initial start up cost is $15000.

5. The company spends $57000 to manufacture 2000 handbands.

Step-by-step explanation:

We are given the cost function for manufacturing 'h' amount of handbands and it is provided that there was initial start up costs involved.

Now, as the cost function is given by, C(h) = 21h + 15000.

We can see that the initial start up cost is $15000.

As, 'h' is the number of handbands being made. So, 21h in C(h) is the cost of manufacturing 'h' handbands.

Therefore, 21 is the cost of manufacturing one handband.

Since, C(h) = 21h + 15000.

Substituting h = 2000, we get,

C(2000) = 21×2000 + 15000.

i.e. C(2000) = 42000 + 15000.

i.e. C(2000) = 57000.

The company spends $57000 to manufacture 2000 handbands.

Since, we are provided with only cost function, we can not talk about the profit.

Hence, option 1, 3 and 5 are correct.

PLEASE MARK ME BRAINLIST!

7 0
2 years ago
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