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Genrish500 [490]
3 years ago
9

Is the gsce foundation maths paper difficult or straight forward?

Mathematics
1 answer:
Sati [7]3 years ago
6 0

Answer:

depends on how you understand math.

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F(x)=-x^2+3 find f(-2)
Black_prince [1.1K]

Answer:

f(-2) = -1

Step-by-step explanation:

f(x) = -x^2 + 3

f(-2) means when x is -2

Shown in the graph below, the point of solution is: (-2,-1), so when x is -2 y is -1

8 0
3 years ago
A football team loses 3 yards, gains 12 yards, gains 10 yards, and then loses 15 yards. Did the team gain yards or lose yards ov
e-lub [12.9K]

Answer: the answer is 4

Step-by-step explanation:

5 0
3 years ago
2.A production process manufactures items with weights that are normally distributed with mean 10 pounds and standard deviation
Vesna [10]

Answer:

Step-by-step explanation:

Given that:

population mean = 10

standard deviation = 0.1

sample mean = 9.8 < x > 10.2

The z score can be computed as:

z = \dfrac{\bar x - \mu}{\sigma}

if x > 10.2

z = \dfrac{10.2- 10}{0.1}

z = \dfrac{0.2}{0.1}

z = 2

If x < 9.8

z = \dfrac{9.8- 10}{0.1}

z = \dfrac{-0.2}{0.1}

z = -2

The p-value = P (z ≤ 2) + P (z ≥ 2)

The p-value = P (z ≤ 2) + ( 1 -  P (z ≥ 2)

p-value = 0.022750 +(1 -   0.97725)

p-value = 0.022750 +  0.022750

p-value = 0.0455

Therefore; the probability of defectives  = 4.55%

the probability of acceptable = 1 - the probability of defectives

the probability of acceptable = 1 - 0.0455

the probability of acceptable = 0.9545

the probability of acceptable = 95.45%

4.55% are defective or 95.45% is acceptable.

sampling distribution of proportions:

sample size n=1000

p = 0.0455

The z - score for this distribution at most 5% of the items is;

z = \dfrac{0.05 - 0.0455}{\sqrt{\dfrac{0.0455\times 0.9545}{1000}}}

z = \dfrac{0.0045}{\sqrt{\dfrac{0.04342975}{1000}}}

z = \dfrac{0.0045}{\sqrt{4.342975 \times 10^{-5}}}

z = 0.6828

The p-value = P(z ≤ 0.6828)

From the z tables

p-value = 0.7526

Thus, the probability that at most 5% of the items in a given batch will be defective = 0.7526

The z - score for this distribution for at least 85% of the items is;

z = \dfrac{0.85 - 0.9545}{\sqrt{\dfrac{0.0455\times 0.9545}{1000}}}

z = \dfrac{-0.1045}{\sqrt{\dfrac{0.04342975}{1000}}}

z = −15.86

p-value = P(z ≥  -15.86)

p-value = 1 - P(z <  -15.86)

p-value = 1 - 0

p-value = 1

Thus, the probability that at least 85% of these items in a given batch will be acceptable = 1

6 0
3 years ago
J is 14 less than 22 as an equation<br> with what j=
Olegator [25]
22 - 14 = 8 

so i think j = 8
4 0
3 years ago
Rewrite 1 / 6 barrels over 2 over 5 hours as a unit rate
Akimi4 [234]

Answer:

5/12 barrel/hour

Step-by-step explanation:

 Type this as a fraction:

  (1/6) barrel

--------------------

  (2/5) hours

Division by 2/5 is equivalent to multiplication by 5/2:

1                5

--- barrel * -------------- = 5/12 barrel/hour

6                2  hours

Alternatively, this problem could be done using decimal fractions:

0.1667 barrel

-------------------- = 0.416666 barrel/hour  =  5/12 barrel/hour

0.4 hours

5 0
3 years ago
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