Answer:
12 feet per second.
Step-by-step explanation:
Please consider the complete question.
Ian tosses a bone up in the air for his dog, Spot. The height, h, in feet, that Spot is above the ground at the time t seconds after she jumps for the bone can be represented
.
What is Spot's average rate of ascent, in feet per second, from the time she jumps into the air to the time she catches the bone at t=1/2?
We will use average rate of change formula to solve our given problem.
Therefore, Spot's average rate of ascent is 12 feet per second.
Basically you just need to multiply the two fractions together to get the depth of the turtle. Therefore the turtle is 3/12 miles deep or 1/4 mile deep.
Answer:
Step-by-step explanation:
a) (a + b)² = (a + b) * (a +b)
(a + b)³ = (a + b) * (a +b) * (a +b)
a²- b² = (a +b) (a - b)
Here (a + b) is common in all the three expressions
HCF = (a + b)
b) (x - 1) = (x - 1)
x² - 1 = (x - 1) * (x + 1)
(x³ - 1) = (x - 1) (x² + x + 1)
HCF = (x -1)
Answer:
The proposed equation is solved as follows:
2X + 7 = 21
2X = 21 - 7
2X = 14
X = 14 / 2
X = 7
The value of X is 7.
A first degree equation is an algebraic equation in which each term is either a constant or a product of a fixed term on a single variable. Therefore, this equation is a first degree one, since it only has a single variable, which is X.
