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Klio2033 [76]
3 years ago
8

The area of a parallelogram is 31.5 ft and the height is 6.3 ft. What is the length of the base?

Mathematics
2 answers:
vlabodo [156]3 years ago
5 0
Hello!

To find the missing length, I believe you'll need to divide 31.5 by 6.3. To find the Area of a parallelogram, the formula would be A=bh. Once you've divided 31.5 by 6.3, you'll get 5 for your missing length. You can also check your answer by multiplying 6.3 w/ 5 to get 31.5

I hope this helps!
makvit [3.9K]3 years ago
4 0
The base is 5 because when you divide 31.5 by 6.3 it's 5
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Answer:

the answer is x=0 and x=2

Step-by-step explanation:

6 0
3 years ago
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"A study conducted at a certain college shows that 56% of the school's graduates find a job in their chosen field within a year
KiRa [710]

Answer:

99.27% probability that among 6 randomly selected graduates, at least one finds a job in his or her chosen field within a year of graduating.

Step-by-step explanation:

For each student, there are only two possible outcomes. Either they find a job in their chosen field within one year of graduating, or they do not. The probability of a student finding a job in their chosen field within one year of graduating is independent of other students. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

56% of the school's graduates find a job in their chosen field within a year after graduation.

This means that p = 0.56

Find the probability that among 6 randomly selected graduates, at least one finds a job in his or her chosen field within a year of graduating.

This is P(X \geq 1) when n = 6.

Either none find a job, or at least one does. The sum of the probabilities of these events is decimal 1. So

P(X = 0) + P(X \geq 1) = 1

P(X \geq 1) = 1 - P(X = 0)

In which

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{6,0}.(0.56)^{0}.(0.44)^{6} = 0.0073

P(X \geq 1) = 1 - P(X = 0) = 1 - 0.0073 = 0.9927

99.27% probability that among 6 randomly selected graduates, at least one finds a job in his or her chosen field within a year of graduating.

8 0
3 years ago
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kenny6666 [7]
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4 0
3 years ago
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3900 workers in 3 buildings. twice as many work in largest building as the smallest of the 3 . there are 500 more workers in the
Svetllana [295]
<h3><u>Question:</u></h3>

There are 3900 workers in the three main buildings downtown. Twice as many people work in the largest building as in the smallest of the three. There are 500 more workers in the second-largest building than in the smallest building. How many workers are in each building?

<h3><u>Answer:</u></h3>

There are 850 workers in smallest building and 1700 workers in largest building and 1350 workers in second largest building

<h3><u>Solution:</u></h3>

Let "b" be the number of workers in smallest building

Given that Twice as many people work in the largest building as in the smallest of the three

number of workers in largest building = 2b

Given that There are 500 more workers in the second-largest building than in the smallest building

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Given that there are 3900 workers in 3 buildings

b + 2b + 500 + b = 3900

4b + 500 = 3900

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b = 850

Thus there are 850 workers in smallest building

workers in largest building = 2b = 2(850) = 1700

workers in second largest building = 500 + b = 500 + 850 = 1350

Thus there are 850 workers in smallest building and 1700 workers in largest building and 1350 workers in second largest building

6 0
3 years ago
It’s really easy but I don’t know the steps can someone help?
tigry1 [53]

Answer:

x=0

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20+x=20

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(I believe that s is the bisector, please correct me if I am wrong)

3 0
3 years ago
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