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2 years ago

What is the probability of pulling a spade or an ace from the deck?

Mathematics

2 answers:

nydimaria [60]2 years ago

7 0

for a spade to be pulled from a deck of cards is 13/52 chance.

for you to pull an ace from the deck is 4/52.

Yakvenalex [24]2 years ago

3 0

Well add the two together 13/52 + 4/52 = 17/52, but subtract out the ace of spades so you don’t count it twice, so 16/52 or 30.77%

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Dahasolnce [82]

Volume of a sphere and a cone

We have that the equation of the volume of a sphere is given by:

$V=\frac{4}{3}\pi r^3$

We have that the radius of a sphere is half the diameter of it:

Then, the radius of this sphere is

r = 6cm/2 = 3cm

<h2>Finding the volume of a sphere</h2>

We replace r by 3 in the equation:

$\begin{gathered} V=\frac{4}{3}\pi r^3 \\ \downarrow \\ V=\frac{4}{3}\pi\cdot3^3 \end{gathered}$

Since 3³ = 3 · 3 · 3 = 27

$\begin{gathered} V=\frac{4}{3}\pi3^3 \\ \downarrow \\ V=\frac{4}{3}\pi\cdot27 \end{gathered}$

If we use π = 3.14:

$\begin{gathered} V=\frac{4}{3}\pi\cdot27 \\ \downarrow \\ V=\frac{4}{3}\cdot3.14\cdot27 \\ \downarrow \\ V=4.18\bar{6}\cdot27 \end{gathered}$

Rounding the first factor to the nearest hundredth (two digits after the decimal), we have:

4.18666... ≅ 4.19

Then, we have that:

$\begin{gathered} V=\frac{4}{3}\pi\cdot27 \\ \downarrow \\ V=4.19\cdot27 \\ =113.13 \end{gathered}$

Then, we have that:

<h2>Finding the volume of a cone</h2>

We have that the volume of a cone is given by:

$V=\frac{1}{3}\pi r^2h$

where r is the radius of its base and h is the height:

Then, in this case

r = 3

h = 6

and

π = 3.14

Replacing in the equation for the volume:

$\begin{gathered} V=\frac{1}{3}\pi r^2h \\ \downarrow \\ V=\frac{1}{3}\cdot3.14\cdot3^2\cdot6 \end{gathered}$

Then, we have:

3² = 9

$\begin{gathered} V=\frac{1}{3}\cdot3.14\cdot3^2\cdot6 \\ \downarrow \\ V=\frac{1}{3}\cdot3.14\cdot9\cdot6 \\ V=\frac{1}{3}\cdot3.14\cdot54 \\ V=56.52 \\ \end{gathered}$

Answer: the volume of the cone that has the same circular base and height is 56.52 cm³

5 0

8 months ago

A room contains three urns: u1, u2, u3. u1 contains 3 red and 2 yellow marbles. u2 contains 3 red and 7 yellow marbles. u3 conta

Archy [21]

Answer:

$\dfrac{11}{30}$

Step-by-step explanation:

Urn U1: 3 red and 2 yellow marbles, in total 5 marbles.

The probability to select red marble is $\dfrac{3}{5}=0.6.$

Urn U2: 3 red and 7 yellow marbles, in total 10 marbles.

The probability to select red marble is $\dfrac{3}{10}=0.3.$

Urn U1: 1 red and 4 yellow marbles, in total 5 marbles.

The probability to select red marble is $\dfrac{1}{5}=0.2.$

The probability to choose each urn is the same and is equal to $\frac{1}{3}.$

Thus, the probability that the marble is red is

$\dfrac{1}{3}\cdot 0.6+\dfrac{1}{3}\cdot 0.3+\dfrac{1}{3}\cdot 0.2=\dfrac{1.1}{3}=\dfrac{11}{30}.$

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2 years ago

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fiasKO [112]

Answer:

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3 years ago

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Step-by-step explanation:

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